y=-0.04x^2+8.3x+4.3 when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0 0=-0.04x^2+8.3x+4.3 use quadratic formula if you have ax^2+bx+c=0, then x= a=-0.04 b=8.3 c=4.3 x= x=208.017 or -0.516785 xrepresents horizontal distance you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards therefor x=280.017 is the answer 208.02 m