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<h2>
Answer: 31 & 32</h2>
Step-by-step explanation:
So we first need to assign letters to represent the numbers.
Let 'a' be the larger number and 'b' the smaller.
Now we can use this to write equations that we can solve simultaneously to find both 'a' and 'b'.
according to the question:
a + 4b = 156 [1]
a - b = 1 [2] (this is because the integers are consecutive
We can rearrange [2] to make 'a' the subject: a = b + 1 [3]
We can then substitute [3] into [1] and solve for b
(b + 1) + 4b = 156
5b = 155
b = 31
Now we can find 'a' using [3]
a = 31 + 1
a = 32
Answer:
Solution given:
sin y = -4/5
p/h=4/5
p=4
h=5
b=√{5²-4²)=3
cos y = b/h=-3/5
again
cos x=12/13
b/h=12/13
b=12
h=13
p=√(13²-12²)=5
sin x=p/h=5/13
now
sin[x-y]=sinxcosy-cosxsiny
=5/13×-3/5-(12/13×-4/5)=33/65 is your answer.
Answer:
what are the drop down words.
Answer:
5000
Step-by-step explanation:
