Answer:
h(t) = -16t^2 + 40t + 120
h(t) = -16(t^2 - 5/2*t) + 120
h(t) = -16(t^2 - 5/2*t + (5/4)^2 - (5/4)^2) + 120
h(t) = -16(t^2 - 5/2*t + (5/4)^2 - 25/16) + 120
h(t) = -16(t^2 - 5/2*t + (5/4)^2) + 120 + 25
h(t) = -16(t - 5/4)^2 + 145
The rock needs 5/4 = 1.25 seconds to travel to the highest point wich is 145 m high.
-6a-5=-95 Given
-6(15)-5=-95 Substitution
a=15 idk the reason im not real good at this but i tried!
Hope you have a nice day
Answer: The measurement of ∠EFG is equal to 70°.
Step-by-step explanation:
Two interior angles who are always opposite to an exterior angle sums to that exterior angle. So we would start as the following:
(6x - 10) + 38 = 7x + 18
In order to find m∠EFG, we must first isolate x. In order to do that, we first add like terms together on both sides.
(6x - 10) + 38 = 7x + 18
6x + 28 = 7x + 18
We then substract 18 on both sides.
6x + 10 = 7x
We finally substract 6x from both sides in order to have the value of x.
x = 10
Now that we know the value of x, we substitute it in our the equation in order to find m∠EFG.
m∠EFG = 6x + 10
m∠EFG = 6(10) + 10
m∠EFG = 60 + 10
m∠EFG = 70
Answer:
Step-by-step explanation:
The first step is to find the slant height of the cone. Using the pythagorean theorem, you can find that 
cm. Plugging this into the equation, you get 
. Hope this helps!
Answer:
Step-by-step explanation:
p=10(q-3r)/r
Cross multiply
pr = 10(q-3r)
pr = 10q - 30r
Pr + 30r = 10q
r(p + 30) = 10q
r = 10q/(p + 30)
