Answer:
dA/dt = 31 in²/ sec
Step-by-step explanation:
The area of the triangle is:
A(t) = (1/2)*b*h where b is the base and h the height
Differentiation on both sides of the equation we obtain
dA/dt = (1/2)* db/dt * h + (1/2)* dh/dt * b (1)
db/dt = 3 in/sec
dh/dt = 2 n/sec
b = 10 in
h = 14 in
By substitution in (1)
dA/dt = 0,5* 3*14 + 0,5* 2*10
dA/dt = 21 in² /sec + 10 in²/sc
dA/dt = 31 in²/ sec
Answer:
∠RQS = 156
Step-by-step explanation:
m∠TQS = 24
∠TQS and ∠RQS are linear pair. Linear pair are two adjacent angles and their sum is 180
∠TQS + ∠RQS = 180
24 + ∠RQS = 180
∠RQS = 180 - 24
∠RQS = 156
Ok fist you wanna change your question into a equation so it would turn into x-6 y=4 and 4.3x - 18 y = 4 then multiple both sides and that pups give you 43x - 180 y = 40 and eliminate one variable and I don’t wanna keep explaining but the the answer is
ANSWER: (x , y ) = (- 80 over 13, and - 22 over 13
Given options : Two intersecting circles are drawn with a radius in each marked. the image will be linked.
Given options : An equilateral triangle inscribed in a circle
A square inscribed in a circle
A regular pentagon inscribed in a circle
A regular hexagon inscribed in a circle.
<u>Note. When we join an intersection point of two circles and centers of the circles it would form an equilateral triangle that would be inscribe inside a common portion of both circles..</u>
Therefore, an equilateral triangle inscribed in a circle would be correct option.
She is completing an equilateral triangle inscribed in a circle.
Answer:
x = -2, proven below.
Step-by-step explanation:
3x + 7 + 2(4x+1) = 3(x-1) - 4
3x + 7 + 8x + 2 = 3x - 3 - 4
9 + 11x = 3x - 7
16 + 11x = 3x
16 = - 8x
-2 = x
