Answer:
B
Step-by-step explanation:
pls mark me brainless pls
Answer: New York
Step-by-step explanation:
Answer:
solution
given=3a+3a^2+3a^3+....+...+...3an
first term(t1)=3a
second term(t2)=3a^2
third term(t3)=3a^3
for arithmetic mean ,d1=d2
d1=t2_t1=3a^2_3a=3a(a_1)
d2=3a^3_3a^2=3a^2(a_1)
here d1 is not equal to d2.
so it's not an arithmetic series.
Again,for geometric mean,r1=r2
r1=d2/d1=3a^2/3a=a
r2=d3/d2=3a^3/3a^2=a
here ,r1 is equal to r2.
so ,it's an geometric series.
Answer:
obtuse
Step-by-step explanation:
The key thing to remember when you're working a problem like this is that
the cube has no memory ... it doesn't know what happened on the last roll,
so the chance of any particular thing happening on the 2nd roll, or on the
100th roll, is the same as it was on the first roll.
Probability of success = (number of ways to succeed) / (total possibilities)
Number of ways for a 4 to come up . . 1
Total possible results of the roll . . . . . 6
Probability of rolling a 4 . . . . . 1 / 6 .
Probability of rolling two 4s . . . (1/6) x (1/6)
Probability of rolling three 4s . . (1/6) x (1/6) x (1/6) = 1/216 = about <em>0.46%</em> .
