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tamaranim1 [39]
3 years ago
5

The price of an item is $35, but you have to pay $38.22. What is the sales tax rate?

Mathematics
1 answer:
bixtya [17]3 years ago
7 0
The answer would be $3.22

$38.22-$35 = $3.22
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Earl E. Bird se levanta às 8h para trabalhar. Quando ele dirige a uma velocidade média de 40 mph, ele se atrasa 3 minutos. Quand
tatiyna

Answer: 48 millas por hora

Step-by-step explanation: 40t + 2= 60t - 3,  es t = .25.

la distancia de su casa a su trabajo es 40(0.25 +0.05) =12 millas allí para su velocidad promedio debería ser 12/0.25 = 48 millas por hora

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3 years ago
If p is the original price of a car, which equation best represents the situation
slava [35]

Answer:

p - 3000 = 16000

Step-by-step explanation:

none of the options given are correct

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3 years ago
And wins a metal in the shape of a circle for finishing a marathon which statements about the metals are true use 3.14 for pi. S
PilotLPTM [1.2K]

Answer:

The true statements are:

C. If the metal has a radius of 2.5 inches then it has an area of 19.625 in.²

D. If the metal has a diameter of 3 inches and it has a circumference of 9.42 inches.

E. If the metal has a circumference of four pi inches then it has an area of four pi square inches

Step-by-step explanation:

Let us revise the rule of circumference and area of a circle

  • The formula of the circumference of a circle is <em>C = π d</em>, where d is the diameter of the circle OR <em>C = 2πr</em>, where r is the radius of the circle
  • The formula of the area of a circle is <em>A = πr²</em>
  • The radius of a circle is equal to half its diameter

A.

∵ The metal has a circumference of 7π inches

∵ C = 2πr

- Equate πd by 7π

∴ πd = 7π

- Divide both sides by π

∴ d = 7 inches not 3.5 inches

∴ A is not true

B.

∵ The metal has a circumference of 3π inches

∵ C = 2πr

- Equate 2πr by 3π

∴ 2πr = 3π

- Divide both sides by π

∴ 2r = 3

- Divide both sides by 2

∴ r = 1.5 inches

∵ A = πr²

∴ A = π(1.5)²

∴ A = 2.25π inches² not 9π inches²

∴ B is not true

C.

∵ The metal has a radius of 2.5 inches

∴ r = 2.5

∵ A = πr²

∵ π = 3.14

∴ A = 3.14(2.5)²

∴ A = 19.625 inches²

∴ If the metal has a radius of 2.5 inches, then its area is 19.625 in.²

∴ C is true

D.

∵ The metal has a diameter of 3 inches

∴ d = 3

∵ C = πd

∵ π = 3.14

∴ C = 3.14(3)

∴ C = 9.42 inches

∴ If the metal has a diameter of 3 inches, then its circumference

  is 9.42 inches

∴ D is true

E.

∵ The metal has a circumference of 4π inches

∵ C = 2πr

- Equate 2πr by 4π

∴ 2πr = 4π

- Divide both sides by 2π

∴ r = 2

- Now you can find the area

∵ A = πr²

∴ A = π(2)²

∴ A = 4π

∴ If the metal has a circumference of 4π inches, then its area

   is 4π  inches²

∴ E is true

The true statements are:

C. If the metal has a radius of 2.5 inches then it has an area of 19.625 in.²

D. If the metal has a diameter of 3 inches and it has a circumference of 9.42 inches.

E. If the metal has a circumference of four pi inches then it has an area of four pi square inches

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What is the missing length?<br> 7 cm<br> р<br> area<br> 56 cm?<br> HURRY
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Answer:

8

Step-by-step explanation:

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