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2 years ago

Solve 18 and 19 please

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

5 0

Answer:

Step-by-step explanation:

18.

slope of line y=2x-5 is 2

slope of line ⊥ to y=2x-5 is

m=-1/2

eq. of reqd. line through (10,6) with slope -1/2 is

y-6=-1/2(x-10)

multiply by 2

2y-12=-x+10

2y+x=10+12

2y+x=22

2y=-x+22

y=-1/2x+11

19.

slope of line y=12x+5,m=12

eq. of line through (5,2) with slope 12 is

y-2=12(x-5)

y-2=12x-60

y=12x-60+2

y=12x-58

compare with y=mx+b

b=-58

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For water to be a liquid, its temperature must be within 50 Kelvin of 323 Kelvin. Which equation can be used to determine the mi

Margarita [4]

Answer:

Mark as BRAINLIEST plz

|x-323|<50: answer

Step-by-step explanation :

For water to be a liquid, the temperature must be within 50 Kelvin of 323 K.

So, the range of the temperature of water will lie between 50 kelvin more than 323 kelvin and 50 kelvin less than 323.

The equation that can be used to determine the maximum temperature at which water is a liquid can be given by : x < 323 + 50

The equation that can be used to determine the minimum temperature at which water is a liquid can be given by : x > 323 - 50

So the resultant equation can be written as :

|x-323|<50

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4 years ago

Solve an equation to determine the unknown quantity.

Montano1993 [528]

-75 times 5 = 30
Add 75 to 30 =105
105 divided by 5= 21
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3 years ago

How many boxes of oranges should I sell to get $180 if each box is 1 and 1/8 dollar profit

Kipish [7]

That would be 180 / 1 1/8
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8 0

3 years ago

within a kiambu county,students were randomly assigned to one of two mathematics teachers.Mrs.Elite and Mrs. Bright. After the a

DerKrebs [107]

Using the t-distribution, as we have the standard deviation for the samples, it is found that since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if they are equally effective teachers, that is, the subtraction of their means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, we test if they are not equally effective teachers, that is, the subtraction of their means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

<h3>What is the distribution of the differences?</h3>

For Mrs. Elite, we have that:

$\mu_1 = 78, \sigma_1 = 10, n_1 = 30, s_1 = \frac{10}{\sqrt{30}} = 1.82574$

For Mrs. Bright, we have that:

$\mu_2 = 85, \sigma_2 = 15, n_2 = 25, s_2 = \frac{15}{\sqrt{25}} = 3$

For the distribution of differences, we have that:

$\overline{x} = \mu_1 - \mu_2 = 78 - 85 = -7$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{1.82574^2 + 3^2} = 3.5119$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-7 - 0}{3.5119}$

$t = -1.99$

Considering a<em> two-tailed test</em>, as we are testing if the mean is different of a value, with 30 + 25 - 2 = <em>53 df and a significance level of 0.1</em>, the critical value is of $|t^{\ast}| = 1.6741$ .

Since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

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3 years ago

Marks computer weighs 35.769 pounds. What’s the weight of his computer rounded to the nearest hundredth

GaryK [48]

The weight of his computer rounded to the nearest hundredth is 35.77 lb. :)

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3 years ago