The price difference/ the original price and times the whole equation by 100 (to get the percentage).
> ($50/$150) x 100 = 33% (rounded)
Answer:
0.918 is the probability that the sample average sediment density is at most 3.00
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 2.80
Standard Deviation, σ = 0.85
Sample size,n = 35
We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:

P(sample average sediment density is at most 3.00)
Calculation the value from standard normal z table, we have,
0.918 is the probability that the sample average sediment density is at most 3.00
Answer:
48.8 lbs
Step-by-step explanation:
The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:
a/sin(A) = c/sin(C)
x/sin(26°) = 80/sin(134°)
x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds
The larger component force is about 48.8 pounds.
1.3 x 0.4 x 2 = 1.04
0.5 x 0.4 = 0.2
(

(0.5 x 1.2)) x 2 = 0.6
1.04 + 0.2 + 0.6 = 1.84m²
2(2x + 1) = 4x + 2
4x + 2 = 4x + 2
All real numbers are solutions :)