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ch4aika [34]
3 years ago
7

Help Please I did to finsh

Mathematics
2 answers:
ki77a [65]3 years ago
7 0

Step-by-step explanation:

Hello there!

Again, plug this into the Pythagorean Theorem.

a^2+b^2=c^2\\2^2+b^2=6^2\\4+b^2=36\\b^2=32\\b=5.65

:)

mihalych1998 [28]3 years ago
6 0

Answer:

b ≈ 6

Step-by-step explanation:

You can use the Pythagorean Theorem to solve this:

a^{2} + b^{2} = c^{2}

All you need to do is plug in the numbers into the formula (in this case, they've given you the hypotenuse, so you need to find the value of the leg):

2^{2} + b^{2} = 6^{2}

4 + b^{2} = 36

<u><em>Subtract 4 from both sides:</em></u>

4 + b^{2} = 36

-4         -4

________

b^{2} = 32

<u><em>Square root:</em></u>

\sqrt{b^2} = \sqrt{32}

b = 5.65

b ≈ 6

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the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
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<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

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The 12th term is given by

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The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

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Thus, the value of a is \frac{3}{65536}

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a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

Thus, the 10th term of the sequence is 12.

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\\ \ast\sf\longmapsto -12.405

\\ \ast\sf\longmapsto -\dfrac{12405}{1000}

  • Simplify until possible

\\ \ast\sf\longmapsto -\dfrac{2481}{200}

Now

\\ \ast\sf\longmapsto -12\dfrac{81}{200}

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