Answer:
<h2><u><em>
x = 4</em></u></h2>
Step-by-step explanation:
that's an equilateral triangle, 3 equal side and 3 equal angles of 60°,
so 10x + 20 = 60
solve with an equation
10x + 20 = 60
10x = 60 - 20
10x = 40
x = 40 : 10
x = 4
--------------------------
check
10 * 4 + 20 =
60°
the answer is good
Step-by-step explanation:
p(y)=2+y+2y²-y³
p(0)=2+(0)+2(0)²-(0)³=2+0+0-0=2
p(1)=2+(1)+2(1)²-1³=2+1+2-1=4
p(2)=2+2+2(2)²-2³=4+8-8=4
<h3>HOPE IT HELPS YOU</h3>
3/4 = 18/24
5/6 = 20/24
18/24 < 20/24
3/4 is not equal to 5/6
Answer:
well, okay. its basically what you wrote. assuming there was missing information.
let's dive right into it.
we'll assume that the problem asks for integers, whole numbers.
if x would be 0,
we would get 9 numbers out, 0, -1, -2, -3, -4, -5, -6, -7 and -8
if x would one, the range would be from 7 to -8, giving us 16 numbers
if x would be 2, the range would be from 14 to -8, giving us 23 numbers (7 more each time we increasex by one)
so the answer isn't a fixed value, but a function.
7x+9
the plus nine is true when x=0 and is still relevant for every other scenario
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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