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3 years ago

HELP ME QUICK PLEASEE!!

Mathematics

1 answer:

Lena [83]3 years ago

3 0

Answer:

A) is a function

B) f(x) is greater

C) x = 12

Step-by-step explanation:

A) Yes, the relation is a function.

A function has a unique input value for each output value. There are no repeated x-values, so this relation is a function.

B) The table says y=6 for x=6.

f(6) = 2(6)+16 = 28

f(x) has a greater value for x=6.

C) Substituting the given information, we have ...

40 = 2x +16

24 = 2x

12 = x

The value of x is 12 when f(x) is 40.

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What we do to one side of the equation we do to the other side

7 * p = -56

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K is the midpoint of PQ, P has

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Answer:

Coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q $(x_2,y_2)$

We will use the formula of midpoint: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We are given midpoint K and $x_1,y_1$ the coordinates of P we need to find $x_2,y_2$ the coordinates of Q.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\$

Now, we can write

$-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16$

So, we get coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

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3 years ago