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Sergio [31]
4 years ago
8

Tomas works as an underwater photographer. He starts at a position that is 17 feet below sea level. He

Mathematics
1 answer:
Reika [66]4 years ago
6 0
He is now 27 feet below sea level or 10 feet below his starting position
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Solve x^2-8x+14=2x+7
LuckyWell [14K]

Answer:

Step-by-step explanation:

x²-8x+ 14 =2x+7

x² - 8x +14 - 2x - 7 = 0

x² - 10x  + 7 = 0

5 0
4 years ago
Jackson used 8/9 of a case of soda to fill 1/3 of the soda machine. How many cases does it take to fill the soda machine?
lorasvet [3.4K]
Jackson used 8/9 of a case of soda to fill 1/3 of the soda machine.
how many cases does it take to fill the soda machine = ?
1/3 means three parts of the soda machine, it means if we fill with 8/9 of a case three times soda machine will be full so,
8/9 + 8/9 + 8/9 = 24/9 
it means it takes the case of soda between 2 and 3.
2.667 approx. cases of soda it take to fill the soda machine.
8 0
4 years ago
Write an equation of the line passing through the point A(2, 0) that is parallel to the line y = 3x−5
satela [25.4K]

Answer:

y = 3x-6

Step-by-step explanation:

y = 3x−5

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

m =3

Parallel lines have the same slope

We have the slope m=3 and a point (2,0)

y = mx+b

y = 3x+b

Substituting the point into the equation to solve for b

0 = 3(2)+b

0 = 6+b

b = -6

y = 3x-6

4 0
3 years ago
Read 2 more answers
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
Andre45 [30]

Answer:

Step-by-step explanation:

Given

there are six integers to win a lottery

case-1 Integer not exceeding 40

no of ways to choose 6 incorrect numbers

=\dfrac{^{34}C_{6}}{^{40}C_{6}}

=0.35

Case-2 no of ways to choose 6 incorrect numbers out of 48 integers

=\dfrac{^{42}C_{6}}{^{48}C_{6}}

=0.427

Case-3 no of ways to choose 6 incorrect numbers out of 56 integers

\dfrac{^{50}C_{6}}{^{56}C_{6}}

=0.489

Cae-4 no of ways to choose 6 incorrect numbers out of 64 integers

\dfrac{^{58}C_{6}}{^{64}C_{6}}

=0.54

6 0
4 years ago
genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. Construct a ​%
Andreas93 [3]

Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The  95%  confidence interval is  0.2392  <  p < 0.3108

No, the confidence interval includes​ 0.25, so the true percentage could easily equal​ 25%

Step-by-step explanation:

From the question we are told that

  The total sample size is  n  =  432 + 164 =596

   The  number of  offspring that is yellow peas is y =  432

   The  number of  offspring that is green peas   is g =  164

   

The sample proportion for offspring that are yellow peas is mathematically evaluated as

        \r p  =  \frac{ 164 }{596}

        \r p  =  0.275

Given the the  confidence level is  95% then the level of significance is mathematically represented as

       \alpha  =  (100 - 95)\%

      \alpha =  5\%  =  0.0 5

The  critical value of  \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} } = 1.96

Generally the margin of error is mathematically evaluated as

        E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }

=>      E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }

=>      E =  0.0358

The  95%  confidence interval is mathematically represented as

      \r p - E  <  p < \r p + E

=>   0.275 -  0.0358  <  p < 0.275 +  0.0358

=>   0.2392  <  p < 0.3108

6 0
3 years ago
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