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malfutka [58]
3 years ago
8

Complete the number sequence 30,80,180,330

Mathematics
1 answer:
galina1969 [7]3 years ago
3 0

Answer: 530

Step-by-step explanation:

First u add 50, 30+50=80, the. 80+100=180, 180+150=330, 330+200= 530 and so on

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To find the height of a pole, a surveyor moves 121 feet away from the base of the pole and then, with a transit 3.6 feet tall, m
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Answer: 139 feet

Step-by-step explanation:I used tan. Tan(44) = x/140

x = 140(Tan 44)

x = 135.196

The transit is 4, so we add that to 135.

This makes 139 feet.

Does this seem right to you?

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Gary bought a bond with a face value of $12,000 and a coupon rate of 6.5%. The bond will mature in 10 years.
Harlamova29_29 [7]

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7 0
3 years ago
This is my next Trigonometry question I am needed help on- I just want to be sure I've got it right, or if not, then the steps I
Reptile [31]
\bf cos(\theta)=\cfrac{3}{5}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}
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\pm\sqrt{16}=b\implies \pm4=b

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6 0
4 years ago
Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and
Pani-rosa [81]

Given Information:

Population proportion = p =  0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$ \sigma_1 = 0.091 $

$ \sigma_2 = 0.050 $

$ \sigma_3 = 0.016 $

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$ \sigma =  \sqrt{\frac{p(1-p)}{n} } $  

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$ \sigma_1 =  \sqrt{\frac{p(1-p)}{n_1} } $

$ \sigma_1 =  \sqrt{\frac{0.55(1-0.55)}{30} } $

$ \sigma_1 = 0.091 $

For sample size n₂ = 100

$ \sigma_2 =  \sqrt{\frac{p(1-p)}{n_2} } $

$ \sigma_2 =  \sqrt{\frac{0.55(1-0.55)}{100} } $

$ \sigma_2 = 0.050 $

For sample size n₃ = 1000

$ \sigma_3 =  \sqrt{\frac{p(1-p)}{n_3} } $

$ \sigma_3 =  \sqrt{\frac{0.55(1-0.55)}{1000} } $

$ \sigma_3 = 0.016 $

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0
4 years ago
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