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Paha777 [63]
3 years ago
11

-5°F to 20°F change temperature

Mathematics
2 answers:
Sever21 [200]3 years ago
7 0
-5, 0, 5, 10, 15, 20
The temperature increased by 25 degrees F
lora16 [44]3 years ago
3 0
There was a 25 degree change in the temperature.
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The length of a school hallway is 115 meters how many kilometers long is the hallway
Levart [38]

Answer:

0.115 kilometers

Step-by-step explanation:

One kilometer is equal to 1,000 meters, so 115 meters is

115/1,000 kilometers,  or 0.115 kilometers

4 0
3 years ago
9. Rick borrowed $50 from his sister for 3 months (1/4 year). She charged him 14% interest. How much interest will Rick have to
True [87]
-4x-6y+16. Thats the answer
5 0
3 years ago
The clothing store marked down all their shirts by 30%. If a shirt originally cost $24, what is the sale price of the shirt?
Alona [7]

Answer:

$16.80

Step-by-step explanation:

Since the shirts are marked down by 30%, you need to multiply the cost of the shirt by the percentage.

$24 × 0.3 = $7.20

Next, subtract the discount from the original price to find the discounted price.

$24 - $7.20 = $16.80

3 0
3 years ago
Plz help me calculate this
krok68 [10]

Answer:

17

Step-by-step explanation:

the rise is the new minus the old.

9 - -8 = 9+8 = 17

4 0
3 years ago
Read 2 more answers
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
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