There are several conditions where triangles can be proved similar:
AA - where two of the angles are same.
SAS - where two sides of a triangle compare to the corresponding sides in the other are in same proportion, and the angle in the middle are equal.
SSS - Where all sides in a triangle and the corresponding sides are in the same proportion.
In the case above, we can only use the method of SAS, as only two sides of the triangles are given.
<HMG = <JMK (vertically opposite angles)
HM/MK = 8/12 = 2/3
GM/MJ = 6/9 = 2/3
As the two sides of a triangle comparing to the corresponding sides in the other are in same proportion, and the angle in the middle are equal, the above triangles are similar, with the prove of SAS.
Therefore, the answer is C.yes by SAS.
Hope it helps!
Answer
12.56.. I think
umm you haven't said which part of the circles is shaded but I assumed that it's the gap between the two circles
1: a) -51
b) -461
2: a) 18078.415936
b) <span>61715.95</span>
A, F, and G.
The others have breaks in the range or don’t include all real numbers.
Answer:
7x=−x+24 7 x = − x + 24
Step-by-step explanation:
The equations we solved in the last section simplified nicely so that we could use the. Our strategy will involve choosing one side of the equation to be the variable side, and step by step, to isolate the variable terms on one side of the equation
