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3 years ago

Which is equivalent to the following expression (3m^2+2mn-n^2)+(m^2+4mn-n^2)

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

$(3m^2+2mn-n^2)+(m^2+4mn-n^2)\\\\=3m^2+2mn-n^2+m^2+4mn-n^2\qquad\text{combine like terms}\\\\=(3m^2+m^2)+(2mn+4mn)+(-n^2-n^2)\\\\=\boxed{4m^2+6mn-2n^2}$

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Step-by-step explanation:

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4 years ago

Find the area of rectangle, where length is 15 cm and breadth is 7 cm.

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Question :-

Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .

Answer :-

Area of Rectangle is 105 cm² .

$\rule {195pt} {2pt}$

Diagram :-

$\sf{15 \: cm} \\ \quad \quad \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\ \\ \\ \end{array}} \: \: \sf {7 \: cm}\end{gathered}\end{gathered}$

$\rule {195pt} {2pt}$

Solution :-

$\quad \quad$ » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.

For calculating the Area of Rectangle , we will use the Formula :-

$\sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth}$

Therefore , by Substituting the given values in the above Formula :-

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\$

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7}$

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105}$

Hence :-

Area of Rectangle = 105 cm² .

$\underline {\rule {195pt} {4pt}}$

Additional Information :-

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