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Anuta_ua [19.1K]
3 years ago
9

Which is equivalent to the following expression (3m^2+2mn-n^2)+(m^2+4mn-n^2)

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0

Answer:

<h3>4m² + 6mn - 2n²</h3>

Step-by-step explanation:

(3m^2+2mn-n^2)+(m^2+4mn-n^2)\\\\=3m^2+2mn-n^2+m^2+4mn-n^2\qquad\text{combine like terms}\\\\=(3m^2+m^2)+(2mn+4mn)+(-n^2-n^2)\\\\=\boxed{4m^2+6mn-2n^2}

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