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Dmitriy789 [7]
3 years ago
16

Draw an area model. then solve using the standard algorithm. use arrows to match the partial products from your area model to th

e partial products in your algorithm.
a. 273×346
Mathematics
2 answers:
11111nata11111 [884]3 years ago
4 0
The answer to your question of what is 273 times 346 is 94,458
kitty cat2 years ago
0 0

wt anwers 000

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Name two solutions for each inequality.
ahrayia [7]
So,

#1: n  \geq 3 \frac{11}{16} + 4 \frac{1}{2}

Convert to like improper fractions.
n  \geq  \frac{59}{16} +  \frac{72}{16}

Add.
n  \geq  \frac{131}{16}\ or\ 8 \frac{3}{16}

So, one solution could be 8 \frac{3}{16}.

Another solution could by 9.  There is also 10, 11, 12, etc., and all numbers in between.


#2: k \ \textless \  6  \frac{2}{5} * 15

Convert into improper fraction form.
k \ \textless \ \frac{32}{5} * 15

Multiply.
\frac{(2^5)(3)(5)}{5}

Cross-cancel, and we have our final result.
(2^5)(3) = 96
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.
6 0
3 years ago
Solve for u, z, y, or t.<br>​
jekas [21]

Doubt --!!

Where is your question!??????

5 0
2 years ago
Need help can anyone help me???​
Paladinen [302]

Answer:

  it is greater than 45°

Step-by-step explanation:

From the relationship of angles and secants/tangents, we have ...

  m∠GSO = (long arc GO -arc GT)/2

Solving for (long arc GO), we have ...

  2(m∠GSO) +arc GT = (long arc GO)

We know that (long arc GO) > 180°, so we can write ...

  2(m∠GSO) +90° > 180° . . . . arc GT = 90°

  2(m∠GSO) > 90° . . . . . . subtract 90°

  m∠GSO > 45° . . . . . . . . divide by 2

_____

<em>Alternate solution</em>

Inscribed ∠GOT has half the measure of arc GT, so is 45°.

You know that if angle G were 90°, then the right triangle would be isosceles, and angle S would also be 45°. In this triangle, arc GTO is less than 180°, so angle G is less than 90°.

When angle G gets smaller, the sum of angles remains the same, so angle S must be larger than 45°.

This reasoning is written more formally in the math above.

8 0
3 years ago
Who will answer first i will mark the brainliest
m_a_m_a [10]

Answer:

It is b

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Sam opened a savings account with a deposit of $50. Every month after that, he
Alexeev081 [22]

Step-by-step explanation:

It is given that,

Sam opened a savings account with a deposit of $50. Every month after that, he  deposited $20 more.

It is not a proportional relationship. As initial amount was $50 and every month he deposited $20 more. The ratio is not constant for the deposited amounts.

To make the relationship proportional, he must start with zero balance and then should have deposited $20 every month.

7 0
3 years ago
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