Ask question

Ask question

All categories

3 years ago

16

Draw an area model. then solve using the standard algorithm. use arrows to match the partial products from your area model to th

e partial products in your algorithm.
a. 273×346

2 answers:

11111nata11111 [884]3 years ago

4 0

The answer to your question of what is 273 times 346 is 94,458

kitty cat2 years ago

0 0

wt anwers 000

You might be interested in

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

6 0

3 years ago

Solve for u, z, y, or t.<br>

jekas [21]

Doubt --!!

Where is your question!??????

5 0

2 years ago

Need help can anyone help me???

Paladinen [302]

Answer:

it is greater than 45°

Step-by-step explanation:

From the relationship of angles and secants/tangents, we have ...

m∠GSO = (long arc GO -arc GT)/2

Solving for (long arc GO), we have ...

2(m∠GSO) +arc GT = (long arc GO)

We know that (long arc GO) > 180°, so we can write ...

2(m∠GSO) +90° > 180° . . . . arc GT = 90°

2(m∠GSO) > 90° . . . . . . subtract 90°

m∠GSO > 45° . . . . . . . . divide by 2

_____

<em>Alternate solution</em>

Inscribed ∠GOT has half the measure of arc GT, so is 45°.

You know that if angle G were 90°, then the right triangle would be isosceles, and angle S would also be 45°. In this triangle, arc GTO is less than 180°, so angle G is less than 90°.

When angle G gets smaller, the sum of angles remains the same, so angle S must be larger than 45°.

This reasoning is written more formally in the math above.

8 0

3 years ago

Who will answer first i will mark the brainliest

m_a_m_a [10]

Answer:

It is b

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Sam opened a savings account with a deposit of $50. Every month after that, he

Alexeev081 [22]

Step-by-step explanation:

It is given that,

Sam opened a savings account with a deposit of $50. Every month after that, he deposited $20 more.

It is not a proportional relationship. As initial amount was $50 and every month he deposited $20 more. The ratio is not constant for the deposited amounts.

To make the relationship proportional, he must start with zero balance and then should have deposited $20 every month.

7 0

3 years ago