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2 years ago

What is the 4-day SMA for the following closing prices: $56, $61, $50, $57, $60, $58, and $57.

Mathematics

1 answer:

IgorLugansk [536]2 years ago

8 0

Answer:

In order to find the correct answer you must use finances and use algebraic equations . You may also have to use precalculus. There is a group of answer choices, its really difficult to find the answer without more instructions. I don't understand what answer your looking for. You may be able to find the answer using finances and other detailed measures. Try using graph paper and write down finances I'm trying my best to help you.

Step-by-step explanation:

finances Algebra Precalculus

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Eight kids got to go to the water park for $60.How many students could go for $195?

Stella [2.4K]

60/8=7.5
So that means one child is $7.50
195/7.5=26
26 students

6 0

3 years ago

HELPPPPPP ME PLEASEEEEEEE

alexgriva [62]

Answer:

x = 20

Step-by-step explanation:

This isn't too difficult once you understand it.

The bottom left angle of the left triangle (on the other side of 110), that angle is congruent to the 70 degrees angle. that angle is 70 degrees. y = 90 degrees, 90 + 70 = 160

180 - 160 = 20

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2 years ago

Solve the separable differential equation dtdx=x2+164 and find the particular solution satisfying the initial condition x(0)=9

maria [59]

$\dfrac{dt}{dx} = x^2 + \frac{1}{64} \Rightarrow\ dt = \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ \\ \displaystyle \int 1 dt = \int \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ t = \dfrac{x^3}{3} + \frac{x}{64} + C$

C = 9 because all the x terms go away.

$t = \dfrac{x^3}{3} + \dfrac{x}{64} + 9$

3 0

3 years ago

Four small cakes are shared equally among 5 children what part does each child receive?

erastova [34]

Answer:

0.8 of a cake

Step-by-step explanation:

all you do is divide 4 by 5

4 0

2 years ago

Simplify the expression.<br> -5+i/2i

Lostsunrise [7]

Answer:

$\rm - \dfrac{11}{2}$

Step-by-step explanation:

$\rm Simplify \: the \: following: \\ \rm \longrightarrow - 5 + \dfrac{i}{2} i \\ \\ \rm Combine \: powers. \\ \rm \dfrac{i \times i}{2} = \dfrac{i^{1 + 1}}{2}: \\ \rm \longrightarrow - 5 + \dfrac{i^{1 + 1}}{2} \\ \\ \rm 1 + 1 = 2: \\ \rm \longrightarrow - 5 + \dfrac{i^2}{2} \\ \\ \rm i^2 = -1: \\ \rm \longrightarrow - 5 + \dfrac{( - 1)}{2} \\ \\ \rm \longrightarrow - 5 - \dfrac{1}{2} \\ \\ \rm Put \: - 5 - \dfrac{1}{2} \: over \: the \: common \: denominator \: 2. \\ \rm - 5 - \dfrac{1}{2} = \dfrac{2( - 5)}{2} - \dfrac{1}{2} : \\ \rm \longrightarrow \dfrac{ - 5 \times 2}{2} - \dfrac{1}{2} \\ \\ \rm 2 (-5) = -10: \\ \rm \longrightarrow \dfrac{ - 10}{2} - \dfrac{1}{2} \\ \\ \rm \dfrac{ - 10}{2} - \dfrac{1}{2} = \dfrac{ - 10 - 1}{2} : \\ \rm \longrightarrow \dfrac{ - 10 - 1}{2} \\ \\ \rm -10 - 1 = -11: \\ \rm \longrightarrow - \dfrac{11}{2}$

7 0

3 years ago