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Feliz [49]
3 years ago
5

What is the product 2x(x-4)

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

2x^2-8x

Step-by-step explanation:

The given expression is

2x(x-4)

We need to find the product of 2x(x-4).

According to the distributive property, if a, b and c are three real numbers then

a(b+c)=ab+ac

Using distributive property the given expression can be written as

2x(x)+2x(-4)

2x^2-8x

Therefore, the product of 2x(x-4) is 2x^2-8x.

stealth61 [152]3 years ago
4 0
The answer is 2x^2-8x

^2 means to the power.

Hope this helps!! ;))
Have a grat day!! <3
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What is the greatest common monomial factor of the expression
Yuki888 [10]
You can factor out 36*5=180 and 27*4=108 and find that they have 36 as greatest common divisor. The x and y factors have xy as the best you can divide by. So the factor becomes 36xy

36xy(5y²+3) = 36x5y³ + 27x4y
8 0
3 years ago
Jack said that if you take a number and multiply it by a fraction, the product will always be smaller than what you started with
ELEN [110]

Answer:

Is not correct. The product not always will be smaller.

Step-by-step explanation:

A fraction could increase a number if you multiply it.  

If the numerator is higher to the  denominator,  it will increase it.  

If the numerator is smaller to the  denominator,  it will decrease it.

<u>For example,</u>

10 x 4/3

For fraction multiplication, multiply the numerators and then multiply the denominators to get

10×4/1×3=40/3= 13,33

13,33 is higher than 10.

5 x 10/3

For fraction multiplication, multiply the numerators and then multiply the denominators to get

5×10/1×3=50/3

16,66 is higher than 5.

5 0
3 years ago
Solve similar triangles (advanced)
Reil [10]

Answer:

x = 5

Step-by-step explanation:

Thales' theorem

\frac{9}{3} =\frac{15}{x}

x=\frac{(15)(3)}{9} =\frac{45}{9} =5

hope this helps

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Step-by-step explanation:

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3 years ago
Find a set of scalar parametric equations for the line formed by the two intersecting planes. 3x+3y+2z+2=0 2x−3y+2z−2=0
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The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).

Using x=0, we can find a point on this line by solving the simultaneous equations that remain:

... 3y +2z = -2

... -3y +2z = 2

Adding these, we get

... 4z = 0

... z = 0

so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...

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By letting t=2/3, we can find a point on the line that has integer coefficients. That will be (x, y, z) = (8, -2, -10).

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