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frosja888 [35]
3 years ago
15

Arrange tho following in ascending order: 2/9, 1/3, 5/12, 1/6​

Mathematics
2 answers:
telo118 [61]3 years ago
5 0

Answer:

2/9=0.22

1÷3=0.33

5÷12=0.41

1÷6=0.16

Step-by-step explanation:

5/12

1/3

2/9

1/6

Sergeu [11.5K]3 years ago
4 0

Step-by-step explanation:

5/12, 2/9, 1/6, 1/2 thats the answer

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What value of t makes (-2) +(-11) = t a true sentence?
Bas_tet [7]

Answer:

t = -13

Step-by-step explanation:

Given expression:

  • (-2) +(-11) = t

Solving for t:

  • -13 = t
  • t = -13
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What are the coordinates of (-3,4) when it is reflected over the y-axis.
AysviL [449]

Answer:

D. (4,3)

Step-by-step explanation:

(-3,4)

Reflection in the y-axis:

Same y, -ve x

(3,4)

Reflection in y = x

(x,y) goes to (y,x)

(3,4) goes to (4,3)

3 0
3 years ago
Describe in words where the square root of twenty-four would be plotted on the number line.
Rzqust [24]

The square root of 24 would be plotted between 4 and 5, but closer to 5 on a number line.

<h3>What is a number line?</h3>

A number line is a horizontal line with evenly spaced numerical increments. The numbers on the line will dictate how you answer the number on the line.

A number line in elementary mathematics is a representation of a graduated straight line that serves as an abstraction for real numbers, denoted by \mathbb {R}. Every point on a number line is assumed to be a real number, and every real number is assumed to be a point.

Number lines are extremely adaptable, that can be used to locate numbers, compare numbers, fractions and mixed numbers, decimals, integers, absolute value, addition, subtraction, inequalities, multiples, common denominators, and much more.

The square root of \sqrt{24}=4.899, which is between 4 and 5, but closer to 5 on a number line.

To learn more about number lines, refer:

brainly.com/question/25230781

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5 0
1 year ago
If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f
Anni [7]

Answer:

Part A) Annual \$66,480.95  

Part B) Semiannual \$66,862.38  

Part C) Monthly \$67,195.44  

Part D) Daily \$67,261.54  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

so

Part A) Annual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=1  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{1})^{1*5}  

A=\$47,400(1.07)^{5}  

A=\$66,480.95  

Part B) Semiannual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=2  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{2})^{2*5}  

A=\$47,400(1.035)^{10}  

A=\$66,862.38  

Part C) Monthly

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=12  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{12})^{12*5}  

A=\$47,400(1.0058)^{60}  

A=\$67,195.44  

Part D) Daily

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=365  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{365})^{365*5}  

A=\$47,400(1.0002)^{1,825}  

A=\$67,261.54  

8 0
3 years ago
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