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sp2606 [1]
3 years ago
6

Remember state space refers to the space of all potential possibilities. Which dichotomous questions below will successfully nar

row down the entire state space of "flipping a coin and rolling a normal six-sided die" to just 1 outcome?
1. Did the coin land on heads?
2. Is the value on the die odd?
3. Is the value on the die more than 3?
4. Does the value on die equal 1, 2, 5, or 6?
Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

The correct answers to the question are

1. Did the coin land on heads?

2. Is the value on the die odd?

3. Is the value on the die more than 3?

4. Does the value on die equal 1, 2, 5, or 6?

Step-by-step explanation:

A dichotomous question is one that has only two possible responses or answers such as Yes or No, Agree or Disagree. Dichotomous question are used to obtain distinctively clear responses in a survey. It limits respondents by providing them with the available choices to choose from

A variable is said to be dichotomous if it has only one two states or categories, for example either male or female or for a coin, either head or tail

State Space

In mathematics a state space is a model of a system related to both the inputs and the outputs of the system

Solution

As such the dichotomous questions to narrow down the entire state space of "flipping a coin and rolling a normal six-sided die" to just 1 outcome are

1. Did the coin land on heads?

2. Is the value on the die odd?

3. Is the value on the die more than 3?

4. Does the value on die equal 1, 2, 5, or 6?

The possible answers to the above questions are yes or no

Possibilities for the coin = heads or tails → possible answers are yes or no

possibilities for the die = 1, 2, 3, 4, 5, or 6

while the possibility of a yes for the die requires as follows

1. Either the die is odd, 1, 3, or 5 or

2 The value of the die is more than 3 which gives 4, 5, or 6

3. Is the value on the die equal 1, 2, 5, or 6

All three questions for the die are required to cover all possible outcomes of 1, 2, 3, 4, 5 and 6 yes or no

Hence there is a possibility to pick the right question to get the same answer for both the coin and the die

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Divide 3m 80cm of ribbon in the ratio of 1/3 : 3/4 : 1/2 what is the result?​
JulijaS [17]

Answer:

80 cm / 180 cm / 120 cm

Step-by-step explanation:

the smallest common multiple of 3, 4 and 2 is 12.

so, to be able to truly compare these fractions we need to bring all denominators to .../12.

1/3 = 4/12

3/4 = 9/12

1/2 = 6/12

in total we have therefore 19 (4+9+6) equally large parts of the ribbon that are then combined :

4 parts for the first segment.

9 parts for the second segment

6 parts for the third segment.

so, one part is

380 cm / 19 = 20 cm

therefore the first segment of the ribbon is

4×20 = 80 cm long

the second segment

9×20 = 180 cm long

the third segment

6×20 = 120 cm long

4 0
3 years ago
What is the answer to the question
-BARSIC- [3]

Answer:

From top to bottom:

3

7

6

12

Step-by-step explanation:

You just simply add the number in the top row and the number in the column together.

2 + 1 = 3

4 + 3 = 7

2 + 4 = 6

6 + 6 = 12

5 0
3 years ago
How to tell whether its a prime or composite number
Lunna [17]
Prime numbers have only 2 factors 1 and its number for example:
2, 3, 5, 7, 11, 13, 17, 19, 23

Like this 1*2. Or 3*1

Composite numbers have more than two factors for example :
0, 4, 6, 8, 9, 10, 12, 14 15, 16..

For example 0 has many factors
0 times 3 0times 4

8 0
3 years ago
Read 2 more answers
Two bowls and one cup weigh 800 grams. One bowl and two cups weigh 700 grams. Find the weight of the bowl and the cup
antoniya [11.8K]

Answer:

\large \boxed{\textbf{Bowl = 300 g; cup = 200 g}}  

Step-by-step explanation:

 Let b  = the mass of a bowl  

and c = the mass of a cup  

We have two conditions:  

\begin{array}{lrcl}(1) &2b + c  & = & 800\\(2) & b + 2c & = & 700\\\end{array}

Calculations:  

\begin{array}{lrcll}(3) & 4b + 2c &=  & 1600&\text{ Multiplied (1) by 2}\\& 3b & = & 900&\text{Subtracted (2) from (3)}\\(4) & b & = & \mathbf{300}&\text{Divided each side by 3}\\ & 600 + c & = & 800&\text{Substituted (4) into (2}\\ & c & = & \mathbf{200}\\\end{array}\\\text{The mass of a bowl  is $\large \boxed{\textbf{300 g}}$ and that of a cup is $\large \boxed{\textbf{200 g}}$}

Check:

\begin{array}{rlcrl}2(300) + 200& =800 & & 300 + 2(200) & = 700\\600 + 200 & = 800& & 300 + 400 & = 700\\800 & = 800& & 700 & = 700\\\end{array}

OK.

6 0
3 years ago
Jessica picked oranges for 2 days during school vacation. She was paid $0.45 per basket for the first 100 baskets picked each da
Mama L [17]

Answer:

$91.75

Step-by-step explanation:

Jessica is paid:

  • $0.45 per basket for the first 100 baskets picked;
  • $0.50 per basket for all baskets over 100 picked.

1st day:

Jessica picked 65 baskets of oranges (less than 100)

Jessica is paid 65\cdot \$0.45=\$29.25

2nd day:

Jessica picked 135 baskets of oranges (35 more than 100)

Jessica is paid 100\cdot \$0.45+35\cdot \$0.50=\$45+\$17.50=\$62.50

Altogether Jessica is paid

\$29.25+\$62.50=\$91.75

4 0
3 years ago
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