For rigt triangle with legs legnth a and b and hypotnuse legnth c
a^2+b^2=c^2
we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller
ok so
first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and
hypontuse is 6 more than shorter
c=6+b
sub 3+b for a and 6+b for c in oroiginal equation'
a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero
b-9=0
b=9
b+3=0
b=-3
fasle, legnths cannot be negative
answer is shorter side=9 cm
Answer:
200
Step-by-step explanation:
18 × 10 = 180
20 × 1 = 20
180 + 20 = 200
Answer:
Yes, he earned a Varsity letter because he played in 61% of the games.
Step-by-step explanation:
To know the percent of games he played out of the total, we can do it by dividing the games he played by the total of games and multiply this by 100% to get the percent of games he played:

We solve:
0.611111*100% = 61.11%
So we know that he earned a letter because he played in 61.11% of the games, more than he needed.
Answer:
x = 50.9
Step-by-step explanation:
35.6 = √(15.3²) + √(x²)
35.6 = 15.3 + x
x = 35.6 + 15.3
x = 50.9
Answer:
option B. 18,12,12
Step-by-step explanation:
perimeter= 60 units
(consider a rectangle with sides a,b,c & d in order)
a= 18 units (given)
c=18 units (since opp. sides of a rectangle are equal)
now the remaining length= 60-(18+18)
= 60 - 36
= 24
so the sum of the remaining sides, ie, b+d= 24
since b and d are equal (opp.sides of a rect.)
b=d=24/2=12
therefore, b=12; c=18; d=12
i really hope i'm clear...but if i'm not then please do ask...