Ask question

Ask question

All categories

Tcecarenko [31]

4 years ago

11

Griffin ordered a pair of sneakers online. He had a $16 credit that he applied toward the purchase, and then he used a credit ca

rd to pay for the rest of the cost. If the shoes cost $76, how much did Griffin charge to his credit card when he bought the sneakers?

1 answer:

Ket [755]4 years ago

4 0

Griffin used $60 on his credit card.

16 - 76 = 60

You might be interested in

Case 4 – House Price. A small data set contains information on House Price (Y) in dollars, as well as predictors: number of Cars

yKpoI14uk [10]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

7 0

3 years ago

-7=9+c/5 what's the value of c

Eduardwww [97]

Answer:

C = -80

Step-by-step explanation:

Solve for c by simplifying both sides of the equation, then isolating the variable.

4 0

3 years ago

Read 2 more answers

Given f(x)= 2x^3+kx-1, and x+1 is a factor of f(x), then what is the value of k?

VMariaS [17]

Answer:

put x=-1, and the rest will be easy

5 0

3 years ago

Read 2 more answers

Line L passes through the points (1, 1) and (7, 8). What is the slope of a line that is perpendicular to line L?

asambeis [7]

When a line passes through the two points $(x_{1},y_{1}) and (x_{2},y_{2})$ , its slope is given by the formula $m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

In this question, a line L passes through the points $(1,1) and (7,8)$

So, its slope is given by $m=\frac{8-1}{7-1}$

$m=\frac{7}{6}$

When two lines are perpendicular, then the product of their slopes is -1.

Since, the slope of the line L is $\frac{7}{6}$ , so the slope of the line which is perpendicular to the given line L is $\frac{-6}{7}$ as the product of $\frac{-6}{7} \times \frac{7}{6}=-1$ .

8 0

3 years ago

Using identities, find a)(2 + 3) 2 b) (x+2y) (x-2y)

shutvik [7]

Pop ok you see so the answer here would be frantically elastic

5 0

2 years ago