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3 years ago

C(x) = (x^1/7)(x + 8)

1 answer:

3 0

C(x) = 8/49 x^-6/7 - 48/49 x^-13/7
= 8/49 x^-6/7 (1 - 6/x)
So the inflection point is at x = 6
hope it helps

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Answer:

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2 years ago

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3 years ago

Write a possible explicit formula for the following sequence: -17, -22, -27, -32 an = ?

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3 years ago

How many different 6-digit numbers can be formed by arranging the digits in 332345?

Feliz [49]

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There are digits to be arranged,they are {3,3,2,3,4,5}. And from those ,3 digits are repeated .

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7 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago