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GREYUIT [131]
4 years ago
15

A football team starts on the 10 yard line moving toward the 50 yard line so they can score on the other side of the field. In t

hree plays they gain 14 yards, lose 12 yards, and gain 4 more yards. What yard line do they start their fourth play?
Mathematics
2 answers:
Tju [1.3M]4 years ago
8 0

Answer:

16 yards.

Step-by-step explanation:

They start at 10 yards. They are moving towards the 50 yard line, so gaining yards will add to the 10 yards instead of subtract from the 10 yards.

In the first play, they gain 14 yards. 10 + 14 = 24 yards.

In the second play, they lose 12 yards. 24 - 12 = 12 yards.

In the third play, they gain 4 yards. 12 + 4 = 16 yards, which is where they start their fourth play.

Hope this helps!

sergiy2304 [10]4 years ago
3 0

Answer:

16 yard line

Step-by-step explanation:

The football team is starting on the 10 yard line. In the first play, they move up to the 24 yard line. Then in the second play, they go back to the 12 yard line since they lost 12 yards. Then in the third play, they gain 4 yards so you add 4 to 12. They end up at the 16 yard line after the third play. This means that they're going to start their fourth play at the 16 yard line.

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20 POINTS NO CAP PLEASE HELP ME NEED RIGHT ANSWER
sammy [17]

Answer: -7/9

Step-by-step explanation: 12-19=-7 and 10-19 = -9, so -7/9.

7 0
3 years ago
Read 2 more answers
Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f
schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval:  (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{130}{20} = 6.5

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

S.D = \sqrt{\frac{233.5}{19}} = 3.50

b) Standard Error

= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826

c) Point estimate for the mean time required for all college is given by the sample mean.

\bar{x} = 6.5

d) 90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729  

6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

5 0
4 years ago
Is 1.436 greater than 25/2
Alex Ar [27]

Answer:1.75 (1 3/4) is greater than 1 1/2. 0.25 is equivalent to 1/4. 0.2185 is not equal to 1/3, and 1.436 is less than 25/2 (12 1/2), hope it helped

Step-by-step explanation:

3 0
4 years ago
Does anyone understand this i never get it
JulijaS [17]

Answer: 18

Step-by-step explanation:

6 ÷ 2 = 3

162 ÷ 54 = 3

The constant ratio is 3

6 × 3 = 18

Hope I helped!

5 0
3 years ago
Need help with this question quickly.
Ber [7]

Answer:

106 = 34 +4t

18 t shirts

Step-by-step explanation:

total profit = profit from hats + profit from tshirts

profit from hats = 34

profit from tshirts = 4* t  where t is the number of tshirts sold

total profit = 34 + 4t

The total profit was 106

106 = 34 +4t

Subtract 34 from each side

106-34 = 34-34 +4t

72 = 4t

Divide each side by 4

72/4 = 4t/4

18 = t

He sold 18 t shirts

5 0
3 years ago
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