Answer:
C. Are all real numbers greater than or equal to -8.
Step-by-step explanation:
Real numbers can be said to be all continuous values of quantity, which can be negative or positive values.
The range of h, h(x), in the table given are all real numbers.
The least of the range of h on the table is -8. All the other range values, namely, -7, 1, 17, and 41 are all greater than -8. None is less than -8.
Therefore, we can conclude that the range values of h "are all real numbers greater than or equal to -8".
Answer:
The distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′ is equal to 
Step-by-step explanation:
we know that
To find the distance, apply the Pythagoras Theorem
Let
x ----> the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′

False because x=2 the f =2
Answer:
3003
Step-by-step explanation:
The number of differents menus containing 10 main courses that the restaurant can make if it has 15 main courses from which to chose is calculated through the combination: 15C10. The formula of the combination is: nCr = n! / ((r!) x(n - r)!)
Where r=10 and n=15
Substituting the values to the equation: 15C10 = 15! / (10!)x(10 - 5)! = 3003
Then there are 3003 different menus that a restaurant can makeif it has 15 main courses from which to choose.
<h3>
Answer: 40</h3>
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Explanation:
The old dimensions of the rectangle were 30 by 15.
The new dimensions are 30+x by 15+x, where x is some positive number.
The new rectangle dimensions multiply to 1000
(30+x)(15+x) = 1000
Use the FOIL rule to expand out the left side like so
(30+x)(15+x) = 1000
450+30x+15x+x^2 = 1000
450+45x+x^2 = 1000
x^2+45x+450
Then lets get everything to one side
x^2+45x+450 = 1000
x^2+45x+450-1000 = 0
x^2+45x-550 = 0
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From here we use the quadratic formula
Plug in a = 1, b = 45, and c = -550.


Earlier we defined x to be a positive number. This means we ignore x = -55. It makes no sense to add on a negative amount to each dimension.
The only practical answer is x = 10.
So each dimension is increased by 10 feet.
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If x = 10, then the old dimensions of 30 by 15 bump up to 30+10 = 40 by 15+10 = 25
Then note how 40*25 = 1000, which helps confirm we have the correct dimensions.
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Now go back to the question at hand: we want to find the new width. The old width was 30 feet. The new width is 30+x = 30+10 = 40 feet