Answer:
Los radios de los círculos son
,
,
, respectivamente.
Las áreas de los círculos son
,
,
, respectivamente.
Step-by-step explanation:
La circunferencia (
) se calcula mediante la siguiente fórmula:
(1)
Donde
es el radio del círculo.
Una vez hallado el radio, se determina el área de la figura geométrica (
) mediante la siguiente fórmula:
(2)
Si conocemos que las circunferencias son
,
y
, respectivamente:
1) Radios de los círculos
,
, 
,
, 
2) Áreas de los círculos
,
, 
,
, 
Answer:
x=-8
Step-by-step explanation:
the equation is in standard form of y=ax^2+bx+c
so, to find the vertex, or axis of symmetry do -b/2a.
-16/2(1)=
-8
Answer:
For, "x" greater than 34, the perimeter of the picture frame greater than 152 inches
Solution:
Let "x" be the width of the frame
Given that, The length of a picture frame is 8 inches more than the width
Therefore,
Length = width + 8
Length = x + 8
The perimeter of rectangle is given by formula:
Perimeter = 2(length + width)
Substituting the values we get,
Perimeter = 2(x + 8 + x)
Perimeter = 2(2x + 8)
Perimeter = 4x + 16
The perimeter of the picture frame greater than 152 inches
Perimeter > 152
Therefore, for, "x" greater than 34, the perimeter of the picture frame greater than 152 inches
Step-by-step explanation:
search it up
They are asking what direction is it from point A to point B. hope that helps
Answer: B
Number on the left: x-value
Number on the right: y-value
If there are 2 y-values for one x-value it is NOT considered a function.
For instance in the answer:
(2,3), (2,4), (3,3), (3,4)
You can clearly see that the x-values (2 & 3) repeat more than once; therefore, it is NOT a function.
On the other hand if you have 2 DIFFERENT x-values for the same y-value it IS A FUNCTION.
For ex D: (2,4), (3,4), (5,4), (6,4)
As you can see there are 4 DIFFERENT x-values with same y-value; therefore it is A FUNCTION
To make it easier:
If x-values appear more than once = NOT A FUNCTION
If x-values appear only ONCE = FUNCTION
Remember: y-values are ALLOWED to repeat
I hope this helps. If you have any questions please let me know in the comments.