The length of the curve 
from x = 3 to x = 6 is 192 units
<h3>How to determine the length of the curve?</h3>
The curve is given as:
from x = 3 to x = 6
Start by differentiating the curve function
Evaluate
The length of the curve is calculated using:
This gives
![L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx](https://tex.z-dn.net/?f=L%20%3D%5Cint%5Climits%5E6_3%20%7B%5Csqrt%7B1%20%2B%20%5Bx%289x%5E2%20%2B%206%29%5E%5Cfrac%2012%5D%5E2%7D%5C%20dx)
Expand
This gives
Express as a perfect square
Evaluate the exponent
Differentiate
Expand
L = (6³ + 6) - (3³ + 3)
Evaluate
L = 192
Hence, the length of the curve is 192 units
Read more about curve lengths at:
brainly.com/question/14015568
#SPJ1
Factor
(x+7)(x-2)
Proof
7-2=5
7*-2=-14
Zeros
x+7=0
x=-7
x-2=0
x=2
Final answer: C
Answer:
A. 3 batches
B. 180 cookies
Step-by-step explanation:
Answer:
(B). between 2.5 and 3.0 and between 4.0 and 4.5.
Step-by-step explanation:
According to the Question,
- If the value of the function is 0 at x=c, then c is a root or zero of the function. It means the graph of function intersects the x-axis at its zeroes.
From the given table it is clear that the value of function are
x | f(x) | Sign
2.0 | 2.8 | Positive
2.5 | 1.1 | Positive
3.0 | –0.8 | Negative
3.5 | –1.2 | Negative
4.0 | –0.3 | Negative
4.5 | 0.7 | Positive
- The sign of values of function changes in interval 2.5-3.0 and 4.0-4.5. It means the graph of function must intersect the x-axis in intervals 2.5-3.0 and 4.0-4.5. So, the zeros of the function lie between 2.5 and 3.0 and between 4.0 and 4.5.
Therefore, the correct option is B.
