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jonny [76]
3 years ago
10

What is 265,200 rounded to the nearest hundred thousand

Mathematics
2 answers:
MaRussiya [10]3 years ago
6 0

265,000

Hope this helps!

sammy [17]3 years ago
6 0

Because the number in the ten thousands place is over 4, it’s going to turn the 2 in the hundred thousands place into a 3, making the answer 300,000

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What is the mean of these numbers ? <br> 2,8,4,6,5
MrRa [10]

Answer:

5 is the mean

Step-by-step explanation:

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3 years ago
I can not figure this out for anything. pls help me.
bixtya [17]
Maybe B but let me check better.
4 0
3 years ago
Jack has $6.00 less than twice the amount of money David has. Together they have $45.00. How much money does Jack have
Shalnov [3]

Answer:

Jack - $28

David - $17

Step-by-step explanation:

Jack has 2d-6 where d is David's money. David has d money. Together they have 45 and we add the two together.

2d-6+d=45

3d-6=45

3d=51

d=$17

We can then substitute back and find 2(17)-6=34-6=$28.

5 0
3 years ago
What is the volume of a square pyramid if the perimeter of the base is 44 in and the height is 19 in.? Round to the nearest tent
Verdich [7]

Answer:

766.3 square inches

Step-by-step explanation:

The volume of pyramid is given by  

volume = 1/3(area of base) * height of pyramid

Given shape of base is square and

Perimeter of that square is 44inches

We know that perimeter for square is given by 4* length of side

Thus,

44 inches = 4* length of side

 Length of side = 44/4 = 11 inches  

_____________________________________________

Area of square is given by side*side.

Thus, area of square base of pyramid is = 11*11 inches square = 121 inches square

Now that we have area of base and height of pyramid .

Substituting these value in formula for volume of pyramid we have

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Volume of square pyramid rounded to nearest tenth is 766.3 square inches

4 0
3 years ago
2. Janice and Jasmine were each given a piece of ribbon of equal length. Janice cuts her ribbons into equal lengths of 2 m, whil
Anna35 [415]

Answer:

10m.

Step-by-step explanation:

Since there is no remainder we simply need to find the least common multiple of each of the lengths of Janice and Jasmin's strings until we find a multiple that matches for each. Like so...

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2*3 = 6

2*4 = 8

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Finally, we have found the first common multiple which is 10m. That means that the shortest equal length for both Janice's and Jasmin's ribbon is 10m.

8 0
3 years ago
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