Question

A man shares a $1,200,00 inheritance between his 3 sons in ratio 1: 3: 6. Calculate the difference between the largest share and the smallest share.

Answer 1

A man's inheritance money = $1200

Given :

He shared his inheritance between his 3 sons in the ratio 1:3:6

Then, the money the first son got :

$= \tt \frac{1}{10} \: of \: 1200$

$=\tt \frac{1}{10} \times 1200$

$=\tt \frac{1 \times 120}{10}$

$= \tt \frac{1200}{10}$

$\color{plum} =\tt\ \: 120$

▪︎Thus, the first son inherited $120.

Money the second son got :

$= \tt \frac{3}{10} \: of \: 1200$

$= \tt \frac{3}{10} \times 1200$

$=\tt \frac{3 \times 1200}{10}$

$= \tt \frac{3600}{10}$

$\color{plum} =\tt \ 360$

▪︎Thus, the second son inherited $360.

Money the third son got :

$=\tt \frac{6}{10} \: of \: 1200$

$=\tt \frac{6}{10} \times 1200$

$= \tt \frac{6 \times 1200}{10}$

$= \tt \frac{7200}{10}$

$\color{plum} = \tt\ 720$

▪︎Thus, the third son inherited $720.

We know that :

The largest share = $720

The smallest share = $120

Difference between the largest and smallest share :

$= \tt720 - 120$

$\color{hotpink}\tt = 600$

●=> Therefore :

▪︎The difference between the largest and smallest share = 600