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Ede4ka [16]
4 years ago
10

Carl has 3 1/2 cups of blueberries. He is storing them in containers that each hold 2/3 cup. How many containers can he fill? Fi

nd the answer and interpret the result​
Mathematics
1 answer:
aivan3 [116]4 years ago
3 0

Answer:

The total number of containers than can be filled  = 5\frac{11}{50}

Step-by-step explanation:

The amount of blueberries Carl has  = 3 1/2 cups

Now, 3\frac{1}{2}  = 3 + \frac{1}{2} = 3 + 0.5  = 3.5

⇒The amount of blueberries Carl has = 3. 5 cups

Also,the amount of blueberries each container can store  = 2/3 cups

Now, \frac{2}{3}   = 0.67

⇒The amount of blueberries each container can store = 0.67 cups

So, \textrm{Total cpus that can be filled by blueberries}  = \frac{\textrm{Toaal amount of blueberries to be stored}}{\textrm{Bluebeeries stored in 1 cup}}

= \frac{3.5 cup}{0.67 cup}  = 5.22

Now,5.22 = 5 + 0.22 = 5 + \frac{22}{100} = 5 + \frac{11}{50}    = 5 \frac{11}{50}

Hence, the total number of cups than cen be filled with the blue berries = 5 11/50

⇒ Blueberries can fill 5 full cups and 11/50th of the 6th cup.

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Answer:

The center of a circle is the point inside a circle that is the same distance from each point on the circle. A circle is the same as 360°. You can divide a circle into smaller portions. A part of a circle is called an arc and an arc is named according to its angle.

Brainlist Pls!

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3 years ago
wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
4 years ago
Find the product. ( 5/6 )( 5/8 )( 3/2 )
AVprozaik [17]

Answer:

The answer is C

Step-by-step explanation:

(5/6)(5/8) = 25/48

(25/48)(3/2) = 75/96

simplify 75/96 = 25/32

7 0
3 years ago
A teacher is four times as old as a student. In 28 years, the student's age will be half of the teacher's age. How old are they
swat32
Here, let the age of student be x and teacher be 4x after 28 years, the teacher is double the age of student. So the age of teacher will be 4x+28 and student will be 2(x+28)
So,
4x+28=2(x+28)
4x+28=2x+56
4x-2x=56-28
2x=28
x=14
Therefore the age of the teacher in present will be
=4x+28
=4*14+28
=84
And age of student will be:
=x+28
=14+28
=42
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7 0
3 years ago
Help I don’t get this
Troyanec [42]

Answer:

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Step-by-step explanation:

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