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2 years ago

Help I don’t get this

Mathematics

1 answer:

Troyanec [42]2 years ago

4 0

Answer:

Step-by-step explanation:

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Dwayne misses 12% of his foul shots and Bryan misses 0.2 of his foul shots. Write 12% and 0.2 as fractions in simplest form. The

Georgia [21]

Answer:

Step-by-step explanation:

0.2*12=

2 2/5

3 0

3 years ago

A pet store sold 36 Siamese cats. If the ratio of Siamese cats to house

White raven [17]

To determine the combined amount of cats sold: is equal to 117 cats

Let the number of Siamese cats sold be S.

Let the number of House cats sold be H.

Let the combined amount of cats sold be C.

<u>Given the following data:</u>

Number of Siamese cats sold = 36

Ratio of S to H = 4:9

Total ratio = 4 + 9 = 13

To determine the combined amount of cats sold:

The ratio of Siamese cats sold is given by:

$\frac{4}{13} \times C=36\\\\4C=36\times 13\\\\4C =468\\\\C=\frac{468}{4}$

C = 117 cats

8 0

2 years ago

6. Emily rides her bike with a constant speed of

qaws [65]

Answer:

42 miles

Step-by-step explanation:

If it's a constant 12 miles per hour then it would be

12 mph x 3 hours = 36

then you would add that with the 1/2 hour for

12 mph x 1/2 hours = 6

36 + 6 = 42 miles traveled

8 0

1 year ago

One root of is x = 6. What are all the factors of the function? Use the Remainder Theorem.

makkiz [27]

3 and 2 should be the only roots

8 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago