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Actually, this is not about angles. It's about the length of the sides in a right triangle.
In EVERY right triangle, the squares of the lengths of the short sides add up
to the square of the length of the longest side. You're in high school math,so
I'm SURE you've heard that in class before ... possibly even just before you
were assigned this problem.
Let's say that again: The squares of the lengths of the sides that meet at
the right angle add up to the square of the length of the longest side. In
the triangle in this particular problem, that means
a² + b² = c²
You know the lengths of 'b' and 'c', so you shouldn't have any trouble finding
the length of 'a'.
Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°,
⊥
, AP = 9, and PM = 16
² +
² =
²
=
+ PM = 9 + 16 = 25
= 25
² =
² +
² = 9² +
²
∴
² = 9² +
²
Similarly we get;
² = 16² +
²
Therefore, we get;
² +
² = 9² +
² + 16² +
² =
² = 25²
2·
² = 25² - (9² + 16²) = 288
² = 288/2 = 144
= √144 = 12
From
² = 9² +
², we get
= √(9² + 12²) = 15
= 15
From,
² = 16² +
², we get;
= √(16² + 12²) = 20
= 20.
The better buy should be buy twelve cans for 7 dollors
Given that,
- twelve cans for7 dollors or 6 cans for 4 dollors.
Based on the above information, the calculation is as follows:
The first option is

= $0.58
The second option

= $0.67
Learn more: brainly.com/question/16911495
Answer:
Area of walkway = 16(x+4) 
Step-by-step explanation:
Length of the sides of the square outdoor = x feet
Area of the square outdoor = length x length
= x * x
=

The square outdoor is surrounded by 4 feet of walkway. So that,
length of the walkway = (x + 2(4))
= (x + 8)
Area of walkway with outdoor = (x + 8)*(x + 8)
= (
+ 16x + 64) 
Area of walkway = Area of walkway with outdoor - Area of the square outdoor
= (
+ 16x + 64) - 
= 16x + 64
Area of walkway = 16(x+4) 