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jeyben [28]
3 years ago
12

A cylinder has a height of 4 inches greater than the radius of its base. Find the radius and the height to the nearest inch if t

he volume of the cylinder is 5pi cubic inches.
Mathematics
2 answers:
valkas [14]3 years ago
8 0

Answer:

d

Step-by-step explanation:

just cus

anastassius [24]3 years ago
7 0

Answer:

h=5in, r=1in

Step-by-step explanation:

The volume of a cylinder is:

V=\pi*r^2*h

where r is the radius and h is the height.

The height is 4 inches greater that the radius, so:

h=r+4in

Substituting this in the formula for volume:

V=\pi*r^2*(r+4)

the volume is V=5\pi in^3

thus:

5\pi in^3=\pi*r^2*(r+4in)

Dividing everything between pi:

5in^3=r^2*(r+4in)

5in^3=r^3*+4r^2

We can see that the solution for this is r=1in

since (1)^3*+4(1)^2=1+4=5

We have the radius, now we find the height:

h=r+4in=1in + 4in = 5in

h=5in, r=1in

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Nollie told the police that Annaliese was a Jew

Step-by-step explanation:

7 0
3 years ago
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How do I Graph y=  –73x+2 .
Romashka-Z-Leto [24]

Answer:

See attachment

Step-by-step explanation:

You can obtain any two points on the graph of y=-73x+2 and use it to draw its graph.

When x=0, y=-73*0+2=2

So you plot (0,2)

When x=1, y=-73*1+2=-71

You again plot (1,-71).

With a straight edge you can now draw a straight line through the two points.

See attachment

4 0
3 years ago
5
Murljashka [212]

Answer:

Step-by-step explanation:

Reflect over the Y axis, then translate (x+[-2], y+[-3])

8 0
2 years ago
Answer the following questions. Make sure to show all your work.
KengaRu [80]

a) Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of  equations

b) since  the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of  equation

In order to show if the given point corresponds to the given function, we will have to substitute the value of x into the function to see if we will have its corresponding y-value

For the point (-0.8, -0.6), substitute x = -0.8 into both functions as shown:

f(x)  = 2x + 1

f(-0.8) = 2(-0.8) + 1

f(-0.8) = -1.6  + 1

f(-0.8) = -0.6

Simiarly;

y = -3(-0.8)- 3

y = 2.4 - 3

y = -0.6

Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of  equations

For the point (1/3, 2), substitute x = 1/3 into both functions as shown:

x = (y+2)/2

x = (2+2)/2

x = 4/2

x = 2

Simiarly;

x + 2 = 3

x = 3-2

x = 1

Since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of  equations

Learn more on systems of equation here: brainly.com/question/847634

5 0
2 years ago
Use the Pythagorean theorem to obtain the function​ D(x) for the length of the diagonal of a double square of width x.
Yuri [45]

Answer:

D(x)= x\sqrt{2}

Step-by-step explanation:

Given

Side = x

Required

Represent the diagonal as a function

Using Pythagoras theorem, the diagonal is:

D^2= Side^2 + Side^2

Substitute x for Side

D^2= x^2 + x^2

D^2= 2x^2

Take the square root of both sides

D= \sqrt{2x^2

Split

D= \sqrt{2} * \sqrt{x^2

D= \sqrt{2} * x

D= x\sqrt{2}

Express as a function.

D(x)= x\sqrt{2}

4 0
3 years ago
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