Question

A cylinder has a height of 4 inches greater than the radius of its base. Find the radius and the height to the nearest inch if the volume of the cylinder is 5pi cubic inches.

Answer 1

Answer:

d

Step-by-step explanation:

just cus

Answer 2

Answer:

$h=5in, r=1in$

Step-by-step explanation:

The volume of a cylinder is:

$V=\pi*r^2*h$

where $r$ is the radius and $h$ is the height.

The height is 4 inches greater that the radius, so:

$h=r+4in$

Substituting this in the formula for volume:

$V=\pi*r^2*(r+4)$

the volume is $V=5\pi in^3$

thus:

$5\pi in^3=\pi*r^2*(r+4in)$

Dividing everything between pi:

$5in^3=r^2*(r+4in)$

$5in^3=r^3*+4r^2$

We can see that the solution for this is $r=1in$

since $(1)^3*+4(1)^2=1+4=5$

We have the radius, now we find the height:

$h=r+4in=1in + 4in = 5in$

$h=5in, r=1in$