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3 years ago

Why did king kong eat a truck algebra with pizzazz answer?

History

2 answers:

Radda [10]3 years ago

8 0

King Kong ate a truck algebra with pizzazz because he always wanted a big Macke. The character of King Kong was created by Merian C. Cooper in a script he wrote for the motion picture. King Kong couldn't exist physically on Earth because of his weight as his bone and muscle tissues would be too weak. However, there once existed a species of great ape which was far larger in mean-average size compared to other types of great apes known as Gigantopithecus. The existence of this ape may have influenced Cooper's creation of the character of King Kong. King Kong first appeared in Japan's, Godzilla series as one of Godzilla's enemy.

lianna [129]3 years ago

4 0

Answer: He always wanted a big Mack.

Explanation:

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8 S: (x+2)² = (x+2) × (x+2) (using distributive property)

= x² + 2x + 2x + 4 (parenthesis expansion)

= x² + 4x + 4 (adding the like terms)

Conclusion: TRUE statement

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13 - E: (a - 5)² = (a - 5) × (a - 5) (using distributive property)

= a² - 5a - 5a + 25 (parenthesis expansion)

= x² - 10a + 25 (adding the like terms)

Conclusion: TRUE statement

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10 - A: (u - 8)² = (u + 8) × (u + 8) (using distributive property)

= u² + 8u + 8u + 64 (parenthesis expansion)

= u² + 16u + 64 (adding the like terms)

Conclusion: TRUE statement

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2 - H : Conclusion: FALSE statement

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18 - G: (3x + 1)² = (3x + 1) × (3x + 1) (using distributive property)

= 9x² + 3x + 3x + 1 (parenthesis expansion)

= 9x² + 6x + 1 (adding the like terms)

Conclusion: TRUE statement

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14 - D: (5t - 2)² = (5t - 2) × (5t - 2) (using distributive property)

= 25t² - 10t - 10t + 4 (parenthesis expansion)

= 25t² - 20t + 4 (adding the like terms)

Conclusion: TRUE statement

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4 - P: Conclusion: FALSE statement

____________________________________________________________

20 - A: (2n + 7)² = (2n + 7) × (2n + 7) (using distributive property)

= 4n² + 14n + 14n + 49 (parenthesis expansion)

= 4t² + 28t + 49 (adding the like terms)

Conclusion: TRUE statement

____________________________________________________________

2 - E: (10d - 4)² = (10d - 4) × (10d - 4) (using distributive property)

= 100d² - 40n - 40n + 16 (parenthesis expansion)

= 100d² - 80t + 16 (adding the like terms)

Conclusion: TRUE statement

____________________________________________________________

5 - k: Conclusion: FALSE statement

____________________________________________________________

7 - R: Conclusion: FALSE statement

____________________________________________________________

2 - E: (x² - 3)² = (x² - 3) × (x² - 3) (using distributive property)

= 4x⁴ - 3x² - 3x² + 9 (parenthesis expansion)

= 4x⁴ - 6x² + 9 (adding the like terms)

Conclusion: TRUE statement

____________________________________________________________

11 - T: Conclusion: FALSE statement

____________________________________________________________

5 - W: (2a + b)² = (2a + b) × (2a + b) (using distributive property)

= 4a² + 2ab + 2ab + b² (parenthesis expansion)

= 4a² + 4ab + b² (adding the like terms)

Conclusion: TRUE statement

____________________________________________________________

15 - A: (3u - 2v)² = (3u - 2v) × (3u - 2v) (using distributive property)

= 9u² - 6uv - 6uv + 4v² (parenthesis expansion)

= 9u² - 12uv + 4v² (adding the like terms)

Conclusion: TRUE statement

____________________________________________________________

6 - E: Conclusion: FALSE statement

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1 - H: (c² - 6d²)² = (c² - 6d²) × (c² - 6d²) (using distributive property)

= c⁴ - 6c²d² - 6c²d² + 36d⁴ (parenthesis expansion)

= c⁴ - 12c²d² + 36d⁴ (adding the like terms)

Conclusion: TRUE statement

____________________________________________________________

21 - I: Conclusion: FALSE statement

____________________________________________________________

Part 2:

The perfect trinomials are:

6 - A

11 - N

7 - Y

21 - C

3 - A

12 - T

16 - B

9 - W

22 - K

17 - I

19 - M

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