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sergij07 [2.7K]
3 years ago
14

make the indicated conversion assume a 360-day year as needed,8months to simplified fraction of a year

Mathematics
1 answer:
balandron [24]3 years ago
6 0
<span>8 months to simplified fraction of a year:

There are 12 months in a year.

8 month = 8/12 = 2/3</span>
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In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
A gold, a silver, and a bronze medal are awarded in an Olympic event. In how many possible ways can the medals be awarded for a
RideAnS [48]

Answer:

720 possible ways

Step-by-step explanation:

The gold is awarded to the first position, the silver is awarded to the second position while the bronze is awarded to the third position.

The first position can be taken by any of the 10 runners

Now, the second position can be taken by remaining 9 runners

while the third position can be taken by the renaming 8 runners.

Thus, the number of ways in which these medals can be awarded = 10 * 9 * 8 = 720 ways

3 0
3 years ago
I need help! Please someone i’ll give brainliest!
Zielflug [23.3K]
I’m literally stuck on the same kind of stuff. i don’t get it
5 0
3 years ago
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Solve 6 &lt; x + 5 &lt; 11 ​
Vanyuwa [196]

Answer:

I think it should be 1  < x ≤ 6

Step-by-step explanation:

7 0
3 years ago
When planning road development, the road commission estimates the future population using the function represented in the table,
Sindrei [870]

The significance of 160,000 in the function is the initial population at the time of the estimation.

The correct option is (C)

<h3>What is data?</h3>

A collection of facts, such as numbers, words, measurements, observations or even just descriptions of things.

Given:

As per the table attached below:

F(x) signify the total population when the time was x hour.

So,  160,000 in the function signifies that the population at starting i.e., initial point.

Learn more about this concept here:

brainly.com/question/17112729

#SPJ1

7 0
2 years ago
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