What is the value of this expression 7 divided by 2

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Tresset [83]

Interpreting the inequality, it is found that the correct option is given by F.

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The first equation is of the line.
The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

$x + 2y = 6$

$2y = 6 - x$

$y = -0.5x + 2$

Thus it is a decreasing line, which removes options J.

We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

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As for the second equation, the normalized equation is:

$3x^2 + 3y^2 = 12$

$3(x^2 + y^2) = 12$

$x^2 + y^2 = 4$

Thus, a circle centered at the origin and with radius 2.
Now, we have to check if the line $x + 2y - 6 = 0$ , with coefficients $a = 1, b = 2, c = -6$ , intersects the circle, of centre $x = 0, y = 0$
First, we find the following distance:

$d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}$

Considering the coefficients of the line and the center of the circle.

$d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1$

This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

3 0

3 years ago

PLEASE HELP!!!

Aliun [14]

Answer:

a. 8.75 M NaOH

b. 0.425 M CuCl₂ or 0.43 M CuCl₂

c. 0.067 M CaCO₃ or 0.07 M CaCO₃

Step-by-step explanation:

Molality is computed using the formula:

$M = \dfrac{Moles\:of\:solute}{Liters\:of\:solution}$

So first thing you need to do is determine how many moles of solute there are and divide it by the solution in liters.

Converting mass to moles, you need to get the mass of each solute per mole. You can use the periodic table to get the atomic mass (which is the grams per mole of each atom) of each of the elements involved. Then add them up and you will have how many grams per mole of each compound.

1. 35.0g of NaOH in 100ml H₂O

Element number of atoms atomic mass TOTAL

Na 1 x 22.99g/mol = 22.99g/mol

O 1 x 16.00g/mol = 16.00g/mol

H 1 x 1.01g/mol =<u> 1.01g/mol</u>

40.00g/mol

This means that the molecular mass of NaOH is 40.00 g/mol

Then we use this to convert 35.0g of NaOH to moles:

$35.0g \:of\:NaOH \times \dfrac{1\:mole\:of\:NaOH}{40.00g\:of\:NaOH} = \dfrac{35.0\:moles\:of\:NaOH}{40.00}=0.875\:moles\:of\:NaOH$

Now that you have the number of moles we divide it by the solution in liters. Before we can do that you have to conver 100ml to L.

$100ml\times\dfrac{1L}{1000ml} = 0.1 L$

Then we divide it:

$\dfrac{0.875\:moles\:of\:NaOH}{0.1L of solution} = 8.75M\: NaOH$

2. 20.0g CuCl₂ in 350ml H₂O

Element number of atoms atomic mass TOTAL

Cu 1 x 63.55g/mol = 63.55g/mol

Cl 2 x 34.45g/mol = <u>70.90g/mol</u>

134.45g/mol

$20.g\:of\:CuCl_2\times\dfrac{1\:mole\:of\:CuCl_2}{134.45\:g\:of\:CuCl_2}=0.1488\:moles\:of\:CuCl_2$

350ml = 0.350L

$\dfrac{0.1488\:moles\:of\:CuCl_2}{0.350L\:of\:solution}=0.425M\:CuCl_2$

3. 3.35g CaCO₃ in 500ml

Element number of atoms atomic mass TOTAL

Ca 1 x 40.08g/mol = 40.08g/mol

C 1 x 12.01g/mol = 12.01g/mol

O 3 x 16.00g/mol =<u> 48.00g/mol</u>

100.09g/mol

$3.35g\:of\:CaCO_3\times\dfrac{1\:mole\:of\:CaCO_3}{100.09\:g\:of\:CaCO_3}=0.0335\:moles\:of\:CaCO_3$

500ml = 0.5L

$\dfrac{0.0335\:moles\:of\:CaCO_3}{0.5L}=0.067M\:CaCo_3$

4 0

3 years ago

6w + 2(4w - 7) simplified

Gemiola [76]

Answer:

14w -14

Step-by-step explanation:

6w + 2(4w - 7)

Distribute

6w+ 8w -14

Combine like terms

14w -14

8 0

3 years ago

Read 2 more answers

A university's freshman class has 6200 students. 4836 of those students are majoring

WINSTONCH [101]

According to the solving 78% of the freshman class are Economics majors.

<h3>What does a percentage mean?</h3>

percentage, a relative figure signifying hundredths of any amount. Since one percent (symbolized as 1%) is equal to one hundredth of something, 100 percent stands for everything, and 200 percent refers to twice the amount specified.

<h3>Why is it called percent?</h3>

The word "percent" comes from the Latin adverb per centum, which means "by the hundred." In the sixteenth century, the Latin expression made its way into English. Later, it was shortened to % with a final period.

<h3>According to the given data:</h3>

It is given that the total number of students in freshman class = 6200

Total number of students majoring in Economics = 4836

Here, we are asked to find the percentage of the freshman class who are majoring in Economics.

Percent of students majoring Economics = (Number of students majoring/ Economics Total number of students) x 100

= $\frac{4836}{6200}$ x 100