Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Answer:
1/2, 2/4
Step-by-step explanation:
The x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is (17, 11)
<h3>Midpoint of coordinate points</h3>
The midpoint of a line is the point that bisects or divides the line into two equal parts
If the line JK is partitioned into the ratio 1:4 with the following coordinates
J(-15, -5) and K(25, 15)
Using the expression below;
M(x, y) =[mx1+nx2/m+n, my1+ny2/m+n]
Substitute the ratio and the coordinates
M(x, y) =[1(-15)+4(25)/4+1, 1(-5)+4(15)/1+4]
M(x, y) = [(85)/5, 55/5]
M(x, y) = (17, 11)
Hence the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is ((17, 11)
Learn more on midpoint of a line here: brainly.com/question/5566419
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