Question

Question 20. SQ is an angle bisector. Find the value of x. Please help!! Struggling

Answer 1

Answer:

The value of x is 6.

Step-by-step explanation:

Given:

∠TSQ = (5x + 3)°

∠RSQ = (10x - 27)°

SQ is the angle bisector of ∠ TSR

To Find:

x = ?

Solution:

Angle Bisector:

A line that splits an angle into two equal angles.

'Bisect' means to divide into two equal parts.

SQ is the angle bisector of ∠ TSR ....Given

∴ $\angle TSQ=\angle RSQ$

Substituting the values we get

$(5x+3)=(10x-27)\\\\10x-5x=27+3\\\\5x=30\\\\\therefore x=\dfrac{30}{5}=6\\\therefore x=6$

The value of x is 6.