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Ugo [173]
3 years ago
15

3.

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

I'm gonna go with letter A. y= 2x - 1

Step-by-step explanation:

Answer:

y = 2x -1

Step-by-step explanation:

the line passes through -1 on the graph

it rises 2

and moves right once

Hope this helps ! (:

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Can someone please help me ASAP​
Sonja [21]

Answer:

x^2 + 5n = 4mx

=> x^2 - 4mx + 5n = 0

D=0 (since one root then roots are equal)

b^2-4ac = 0

(-4m)^2 - 4(1)(5n) = 0

16m^2 - 20n = 0

16m^2 = 20n

8m^2 = 10n

4m^2 = 5n

hope it helps.......

7 0
3 years ago
Brigitte is shorter than 5 feet. (Brigitte's height=h). Help please
KonstantinChe [14]

Brigitte is shorter than 5 feet. (Brigitte's height=h)

We write this in  inequality form

Brigitte's height is h

So 'h' is shorter than 5 feet

Shorter means less than so we use < symbol. We should not use = symbol because height is shorter than 5 not equal to 5.

Suppose if it is given ' height is more than 5 feet ' then we use greater than symbol (>)

h is less than 5 feet

h < 5

Inequality is h < 5

3 0
3 years ago
Read 2 more answers
Which of the following is a solution to 2cos x + 1 = 0? 60° 120° 210° 300°
klasskru [66]
Rewrite   <span>2cos x + 1 = 0    as:

2 cos x = -1, and then cos x = -1/2

x must be in Quadrant II or Quadrant III, since the adj. side is negative.

Note that the angle 120 has adj. side -1 and hyp 2.  So 120 degrees is one solution.  

Now what about a possible 2nd solution, to be found in Quadrant III?  That would be -120 degrees, which has the same terminal line as does 240 degrees.

No soap.

So, the solution is 120 degrees.</span>
6 0
3 years ago
Read 2 more answers
The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th
vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by P(t)=1.394(1.006)^t

To find the derivative you need to:

\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t

To find the population growing at the start of 2014 we say t = 0

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year

To find the population growing at the start of 2015 we say t = 1

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year

To convert billion to million you multiple by 1000

P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year

6 0
3 years ago
Now round 3.152 to the nearest one.
Alika [10]
3


Mark brainliest please


Hope this helps you
8 0
2 years ago
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