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Otrada [13]
3 years ago
14

How do you write 2x in radical form

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0
\sqrt{2x}=2x^{\frac{1}{2}}
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For the following problem, match the name of the number property that was used to get to each step from the previous step.
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3 years ago
Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

#SPJ1

8 0
2 years ago
Anyone help me please<br><img src="https://tex.z-dn.net/?f=6%20%7Bx%7D%5E%7B6%7D%20%20%2B%206%20%7Bx%7D%5E%7B4%7D%20%20%2B%206%2
evablogger [386]

Answer:

(6x^2)(x^4 +x^2 + 1)

Step-by-step explanation:

6x^6 + 6x^4 + 6x^2

split it up into parts

6x^6 = (6x^2) * x^4

6x^4 = (6x^2) * x^2

6x^2 = (6x^2) * 1

so you can take out 6x^2 to get

(6x^2)(x^4 +x^2 + 1)

8 0
3 years ago
Read 2 more answers
What is the domain of the set (-3,5), (2,0), (7,-5)​
Valentin [98]

The domain is all x-values.

The domain is -3, 2, 7

The range is all y-values

The range is 5, 0, -5

Best of Luck!

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3 years ago
Can someone tell me What is 10% of 20
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Answer:

2

Step-by-step explanation:

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