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Otrada [13]
3 years ago
14

How do you write 2x in radical form

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0
\sqrt{2x}=2x^{\frac{1}{2}}
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Which equation represents a line through (-2, 1) that is perpendicular<br> to y = -5x + 2?
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1=-5(-2)+2

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A straight line L is perpendicular to line 3x-2y+4=0. The area of triangle formed by the line L and coordinate axes is 27 sq.uni
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Suppose you start out with a cone of height 8 cm and base radius 6 cm, and you want to change the dimensions in such a way that
NARA [144]

Answer: r ≈ 5.95

Step-by-step explanation:

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S = \pir^{2} + \pir\sqrt{r^{2}+h^{2}}

Differentiating S with respect to r , we have

dS = \frac{dS}{dr} dr + \frac{dS}{dh} dh

\frac{dS}{dr} = (2\pir +\pi\sqrt{h^{2}+r^{2}} + \frac{\pi r^{2} }{\sqrt{h^{2}+r^{2}} }) dr + \frac{\pi rh }{h^{2}+r^{2}  } dh

For the area to remain the same it means dS = 0

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Making dr the subject of formula , we have

(12π + 10π +\frac{18\pi }{5})dr = - (\frac{24\pi }{5} X 0.28)

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dr = - 33.6\pi / 640\pi

dr = 0.05

This means that the radius should decrease by 0.05 for the area to remain the same. That means the radius = 6 - 0.05

r ≈ 5.95

7 0
3 years ago
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