9514 1404 393
Answer:
- relative minimum -6√3 at x = -√3
- relative maximum 6√3 at x = √3
- decreasing on x < -√3 and x > √3
- increasing on -√3 < x < √3
- see below for a graph
Step-by-step explanation:
I find it convenient to draw the graph first when looking for relative extrema.
The function can be differentiated to get ...
f'(x) = -3x^2 +9
This is zero when ...
-3x^2 +9 = 0
x^2 = 3
x = ±√3 . . . . . x-values of relative extrema
Then the extreme values are ...
f(±√3) = x(9 -x^2) = (±√3)(9 -3) = ±6√3
The lower extreme (minimum) corresponds to the lower value of x (-√3), so the extrema are ...
(x, y) = (-√3, -6√3) and (√3, 6√3)
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Since the leading coefficient is negative and the degree is odd, the function is decreasing for values of x below the minimum and above the maximum. It is increasing for values of x between the minimum and the maximum.
decreasing: x < -√3, and √3 < x
increasing: -√3 < x < √3
Answer:
14
Step-by-step explanation:
Answer:
d(A,B)=square root of 34 ≈ 5.831
<em>The question has inconsistent or incomplete data, so I'm filling the holes with key data.</em>
Answer:
<em>Every people at dinner received one-tenth of the original turkey= 0.1</em>
Step-by-step explanation:
<u>Proportions</u>
If some fraction a/b of a whole total M is to be computed and later removed, we proceed as follows
* Compute the portion to be removed as a/b*M
* Subtract it from the total quantity: M-a/b*M=M(1-a/b)
I'm assuming 1/5 of the turkey was lost due to overcooking. It means that (1-1/5) of the turkey remained for dinner, that is, 4/5 of the turkey.
Each people at dinner received the same amount of the remaining, so we must divide 4/5 by 8, to get 4/40, or 1/10. It means that every people at dinner received one-tenth of the original turkey