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Sindrei [870]
3 years ago
10

If a is an integer, prove that (14a + 3, 21a + 4) = 1.

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

(14a+3, 21+4) = 1

Step-by-step explanation:

We are going to use the Euclidean Algorithm to prove that these two integers have a gcd of 1.

gcd (14a + 3, 21a + 4) = gcd (14a+3, 7a + 1) = gcd (1, 7a+1) = 1

Therefore,

(14a + 3, 21a + 4) = 1

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Select the solution to the graph from the following points. Select all that apply.
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Answer:

The solutions are:

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(3 , 2) ⇒ 3rd

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Step-by-step explanation:

To find the solution of the graph let us make the equation of the line by using any two points on the line

The form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (value y at x = 0)

The formula of the slope is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

From the figure

∵ The line passes through points (-3 , 0) and (0 , 1)

- Find the slope of the line

∴ m=\frac{1-0}{0--3}=\frac{1}{3}

- Substitute the value of m in the form of the equation

∴ y = \frac{1}{3} x + b

∵ b is the value of y at x = 0

∵ y = 1 at x = 0 ⇒ y-intercept

∴ b = 1

∴ y = \frac{1}{3} x + 1

Lets substitute the x-coordinate of each point to find the y-coordinate, if the y-coordinate is equal to the y-coordinate of the points, then the point is a solution

Point (-15 , -4)

∵ x = -15

∴ y = \frac{1}{3} (-15) + 1

∴ y = -5 + 1 = -4 ⇒ same value of the point

∴ (-15 , -4) is a solution

Point (-6 , 1)

∵ x = -6

∴ y = \frac{1}{3} (-6) + 1

∴ y = -2 + 1 = -1 ⇒ not the same value of the point

∴ (-6 , 1) is not a solution

Point (3 , 2)

∵ x = 3

∴ y = \frac{1}{3} (3) + 1

∴ y = 1 + 1 = 2 ⇒ same value of the point

∴ (3 , 2) is a solution

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∵ x = 12

∴ y = \frac{1}{3} (12) + 1

∴ y = 4 + 1 = 5 ⇒ not the same value of the point

∴ (12 , 9) is not a solution

Point (21 , 8)

∵ x = 21

∴ y = \frac{1}{3} (21) + 1

∴ y = 7 + 1 = 8 ⇒ same value of the point

∴ (21 , 8) is a solution

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