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blsea [12.9K]
3 years ago
5

I need help solving for this

Mathematics
2 answers:
puteri [66]3 years ago
8 0
I believe each teacher gets half a doughnut and mrs. Davis will have 5 doughnuts left
Ksenya-84 [330]3 years ago
7 0

Answer: 12/15 = 0.8

Step-by-step explanation: There are 12 donuts and 15 teachers, just divide the amount of donuts by the amount of teachers. Hope that helps.

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64,569 rounded to the thousands
Zina [86]
The 4 is in the thousands place and looking to the right of the 4 is a 5. The rule is less than 4 leave it the same; 5 or more add 1 to the number.

So the answer would be 65,000.

3 0
3 years ago
Find the value of x if 196^×=14​
castortr0y [4]

Answer:

x = \frac{1}{2}

Step-by-step explanation:

Note that \sqrt{196} = 14

Expressed in exponent form as

196^{\frac{1}{2} } = 14, thus

x = \frac{1}{2}

7 0
3 years ago
CAN SOMEONE HELP ME FAST
a_sh-v [17]
Answer is <span>A. y=14x

hope that helps</span>
8 0
3 years ago
Read 2 more answers
Express (a+b) ^2 -4 by factorization
NemiM [27]

Step-by-step explanation:

= (a + b) {}^{2}  - 2 { }^{2}  \\ = ( a + b  + 2)(a + b - 2)

in 2nd exp. this is because by using the formula of a2-b2

5 0
3 years ago
A quality control engineer is interested in estimating the proportion of defective items coming off a production line. In a samp
fenix001 [56]

Answer:

The lower bound of a 99% C.I for the proportion of defectives = 0.422

Step-by-step explanation:

From the given information:

The point estimate = sample proportion \hat p

\hat p = \dfrac{x}{n}

\hat p = \dfrac{55}{100}

\hat p = 0.55

At Confidence interval of 99%, the level of significance = 1 - 0.99

= 0.01

Z_{\alpha/2} =Z_{0.01/2} \\ \\ = Z_{0.005} = 2.576

Then the margin of error E = Z_{\alpha/2} \times \sqrt{\dfrac{\hat p(1-\hat p)}{n}}

E = 2.576 \times \sqrt{\dfrac{0.55(1-0.55)}{100}}

E = 2.576 \times \sqrt{\dfrac{0.2475}{100}}

E = 2.576 \times0.04975

E = 0.128156

E ≅ 0.128

At 99% C.I for the population proportion p is: \hat p - E

= 0.55 - 0.128

= 0.422

Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422

6 0
3 years ago
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