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uysha [10]
3 years ago
6

How many days are there in 8 weeks

Mathematics
2 answers:
kodGreya [7K]3 years ago
8 0
1 week: 7 days
8 weeks: 7 times 8
7 times 8=56
The answer would be 56

puteri [66]3 years ago
4 0
1 week=7 days
8 weeks=8 times 7 days
8 weeks=56 days

56 days
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Step-by-step explanation:

The type of graph is quadratic

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Step-by-step explanation: The 18 percent tip basically is saying .18 times 58, which equals 10.44 oh it must be A...NO DONT BE FOOLED, the question is asking for the total bill and not what the percentage of the meal was. so you subtract 10.44 from 58 and get 47.56

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Kyle has 2 peanuts. He eats 1. How much does he have now?
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2-1=1
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Use integration by parts to find the integrals in Exercise.<br> ∫^3_0 3-x/3e^x dx.
Viefleur [7K]

Answer:

8.733046.

Step-by-step explanation:

We have been given a definite integral \int _0^3\:3-\frac{x}{3e^x}dx. We are asked to find the value of the given integral using integration by parts.

Using sum rule of integrals, we will get:

\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx

We will use Integration by parts formula to solve our given problem.

\int\ vdv=uv-\int\ vdu

Let u=x and v'=\frac{1}{e^x}.

Now, we need to find du and v using these values as shown below:

\frac{du}{dx}=\frac{d}{dx}(x)

\frac{du}{dx}=1

du=1dx

du=dx

v'=\frac{1}{e^x}

v=-\frac{1}{e^x}

Substituting our given values in integration by parts formula, we will get:

\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(x*(-\frac{1}{e^x})-\int _0^3(-\frac{1}{e^x})dx)

\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))

\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx=3x-\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))

Compute the boundaries:

3(3)-\frac{1}{3}(-\frac{3}{e^3}- (\frac{1}{e^3}))=9+\frac{4}{3e^3}=9.06638

3(0)-\frac{1}{3}(-\frac{0}{e^0}- (\frac{1}{e^0}))=0-(-\frac{1}{3})=\frac{1}{3}

9.06638-\frac{1}{3}=8.733046

Therefore, the value of the given integral would be 8.733046.

6 0
2 years ago
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