All categories

3 years ago

Some1 help please :) dont answer if u are not 100% sure thank you

Mathematics

2 answers:

Natalija [7]3 years ago

5 0

Answer:

Step-by-step explanation:

It's never negative.

masha68 [24]3 years ago

4 0

D is indeed correct, the function's values never go below 0, meaning never below the x-axis

You might be interested in

A circle with radius of 1 cm sits inside a 3 cm x 3 cm rectangle.

alina1380 [7]

Answer:

6.14

Step-by-step explanation:

Find area of shaded region:

regtangle area - circle area = shaded area

Regtangle area:

3x3=9

Circle area:

Pi (3.14) x radius x radius= 3.14

area all together if shaded region

9-3.14=6.14

4 0

3 years ago

The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of th

kari74 [83]

L= 15
W= 21

Good luck!

4 0

3 years ago

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0

3 years ago

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$