Question

If f(x) = 5x – 1, then f^-1(x)=

Answer 1

Answer:

$\boxed{\sf \ \ \ f^{-1}(x)=\dfrac{x+1}{5} \ \ \ }$

Step-by-step explanation:

hello

f(x)=5x-1

what can we say about $f^{-1}(x) ?$

$(fof^{-1})(x)=x=f(f^{-1}(x))=5f^{-1}(x)-1$

so

$5f^{-1}(x)-1=x\\ 5f^{-1}(x)-1+1=5f^{-1}(x)=x+1 \ \ \ add \ \ 1\\ f^{-1}(x)=\dfrac{x+1}{5} \ \ \ divide \ \ by \ \ 5$

hope this helps