Answer:
A volcano ejected with an initial velocity of 304 feet per second.
The height in feet is given by the equation H=-16t^2+ 304t where t is the time in seconds.
We will use the equation that traces the path of the projectile to determine the following information:
1) The time it takes the projectile to reach its maximum height (using the vertex formula: t=-b/2a)
The equation; H = -16t^2 + 304t, a=-16; b=304
t = -304/2°(-16)
t = 9.5 sec to reach max height
2) The maximum height of the projectile (use the result from part 1 to find the maximum height of the projectile)
t = 9.5
H = -16(9.5^2) + 304(9.5)
h = = -1444 + 2888
h = 1444 ft is the max height
3) Find the time it takes the projectile to return to the ground. Assume that the projectile starts at height H=0.
-16t^2 + 304t = 0
factor out -16t
-16t(t - 19) = 0
t = 19 sec to reach the ground
Step-by-step explanation:
Answer:
-2
Step-by-step explanation:
If we replace all the spots where x is with -3, we get this: (-3)^2 + 5(-3) + 4. Then we get... 9 + -15 + 4 which equals -2
Answer:
718,200 boxes
Step-by-step explanation:
Given the dimension of the storage space = 300ft×200ft×30ft
Dimension of each box = 20in×18in×12in
In order to determine the number of boxes Graphic DesignWorks is able to store, we will divide the Dimension of the storage space the dimension of the box.
Number of boxes = Dimension of storage space/dimension of boxes
We need to convert the dimension of boxes from inches to feet
1inch = 0.0833ft
20inches = 20×0.0833 = 1.666ft
18inches = 18×0.0833 = 1.499ft
12inches = 12×0.0833 = 0.9996ft
Number of boxes = 300×200×30/1.666×1.499×0.9996
Number of boxes = 1800000/2.496
Number of boxes = 721,153.85boxes
Based on the value, the best estimate that is close to the gotten value will be 718,200 boxes
9514 1404 393
Answer:
18 square units
Step-by-step explanation:
Referring to the figure, we see that the base AB has a slope of 1, and the altitude CD has a slope of -1. The number of unit squares crossed by these segments are, respectively 6 and 3, so the length of each is ...
AB = 6√2
CD =3√2
The area is half the product of the base (AB) and height (CD) so is ...
A = 1/2bh = (1/2)(6√2)(3√2) = 18
The area of ΔABC is 18 square units.
_____
<em>Additional comment</em>
It is useful to remember that the diagonal of a unit square is √2. We used that fact here. If you need to figure it using the Pythagorean theorem, you find ...
c² = a² +b²
c = 1² +1² = 2
c = √2
I believe the answer is 63/100 (in fraction form)
and 0.63 in decimal form.