Answer:
Number of year in which population will be 180,000 = 6 year (Approx.)
Step-by-step explanation:
Given:
Population in 2007 = 168,979
Rate of increase in population = 1% = 0.01
Future population = 180,000
Find:
Number of year in which population will be 180,000
Computation:
A = P[1+r]ⁿ
Future population = Population in 2007[1+Rate of increase in population]ⁿ
180,000 = 168,979[1+0.01]ⁿ
180,000 = 168,979[1.01]ⁿ
1.06522 = [1.01]ⁿ
n = 6 (Approx.)
Number of year in which population will be 180,000 = 6 year (Approx.)
Answer:
this is the answer all you had to do was search it up
Answer:
Wouldn't it just be 8?
Step-by-step explanation:
f(8)
8f^1-1
8f^0
8x1
8
Answer:
see explanation
Step-by-step explanation:
Using the rules of exponents
= 
= ![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Given
= 
= ![\frac{1}{\sqrt[b]{y^{a} } }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5Bb%5D%7By%5E%7Ba%7D%20%7D%20%7D)
