Answer:
392in² would be my guess
Step-by-step explanation:
The area of the parallelogram is equal to,
![A=bh](https://tex.z-dn.net/?f=A%3Dbh)
where b is base and h is the length of the height.
Area of parallelogram = 14 inches× 10 inches = 140 in²
There are two parallelograms, the total area of two parallelograms is 280 in².
The area of the triangle is calculated Below
![Area=BH/2](https://tex.z-dn.net/?f=Area%3DBH%2F2)
![Area = (28 inches)-18 inches - 10 inches- / 2 = 112 in^{2}](https://tex.z-dn.net/?f=Area%20%3D%20%2828%20inches%29-18%20inches%20-%2010%20inches-%20%2F%202%20%3D%20112%20in%5E%7B2%7D)
Adding the areas we get --> ![392in^{2}](https://tex.z-dn.net/?f=392in%5E%7B2%7D)
Therefore the Answer will be ![392in^{2}](https://tex.z-dn.net/?f=392in%5E%7B2%7D)
Good Luck with your Assignment!
Have a great day!