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olga2289 [7]
3 years ago
7

When baking a cake, you have a choice of the following pans:

Mathematics
1 answer:
Lorico [155]3 years ago
8 0

Answer:

It is 6x9

Step-by-step explanation:

Simple match 9x6 54 and 7x2 14 well I would rather have 54 units of cake that 14 Lol

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Determine if the fractions are equivalent. Show your work. <br><br> 8. 3/5 6/15
fomenos
They are different the fraction 3/5 is 0.6 in decimal,and the fraction 6/15 is 0.4 in decimal.
Wish that helped.

6 0
3 years ago
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A company makes traffic signs one of those signs can be modeled by an equilateral triangle with the perimeter of 144 inches the
barxatty [35]

Answer:

The height of the larger traffic signs is 51.96 inches

Step-by-step explanation:

Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches

Now, A company makes similar traffic signs of perimeter 1.25 of original

New perimeter will be 1.25x144=180 inches

Let triangle ABC be a larger triangle with 180inches of the perimeter.

It is given that the triangle is an equilateral triangle,

Therefore, Side AB=BC=AC

The perimeter of a triangle ABC is

AB+BC+AC=180

3AB=180

AB=60 inches

Figure show that triangle ABC and AD is the height of the triangle.

Since, the triangle ABC is an equilateral triangle,

AD is the perpendicular bisector of BC

so that,

BD=DC and Angle ADB=90

In right triangle ADB,

Angle D =90 and Angle B =60

Side BD=60/2=30 inches and AB=60 inches

Using Pythagoras theorem,

AD^{2} +BD^{2} =AC^{2}

(AD)^{2} +(30)^{2} =60^{2}

(AD)^{2} =60^{2}-(30)^{2}

AD=51.96 inches

Thus, The height of the larger traffic signs is 51.96 inches

4 0
3 years ago
Each pound of fruit costs $4. Write an expression that shows the total cost of fruit use the variable you identified in the ques
Gnesinka [82]
The expression would be j • $4
5 0
3 years ago
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Solve for the indicated variable in the parentheses<br><br> P = IRT Solve for (T)
KATRIN_1 [288]
P = IRT 

T=P/(IR)

hope helped 
8 0
3 years ago
A one-parameter family of solutions of the DE P' = P( 1 - P) is given below. P = c1et/1 + c1et Does any solution curve pass thro
topjm [15]

Answer:

a. The curve P(t) = -\frac{6e^t}{5-6e^t} passes through the point (0, 6)

b. No solution of the curve P(t) passes through the point (0, 1)

Step-by-step explanation:

Consider the family of the solution of DE P' = P(1 - P) is P = \frac{c_1e^t}{1 + c_1e^t}

a. If any solution passes through the point (0, 6), then there is c_1 such that the point (0, 6) satisfies the solution P = \frac{c_1e^t}{1 + c_1e^t}

Substitute t = 0, P = 6 in P = \frac{c_1e^t}{1 + c_1e^t} and then solve the equation to obtain c_1

P(t) = \frac{c_1e^t}{1 + c_1e^t}\\P(0) = \frac{c_1e^0}{1+c_1e^0}\\ 6 = \frac{c_1}{1 + c_1}\\ c_1 =  -\frac{6}{5}

Therefore, the curve P(t) = -\frac{6e^t}{5 - 6e^t} passes through the point (0, 6)

b.  If any solution passes through the point(0, 1), then there is c_1 such that the point (0, 1) satisfies the solution P = \frac{c_1e^t}{1+c_1e^t}

P(t) = \frac{c_1e^t}{1 + c_1e^t}\\ P(0) = \frac{c_1e^0}{1 + c_1e^0}\\ 1 = \frac{c_1}{1+c_1} \\1 + c_1 = c_1

this is not possible

Hence, there is no curve P(t) that exists which passes through the point (0, 1)

4 0
3 years ago
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