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babunello [35]
2 years ago
12

What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4?

Mathematics
1 answer:
tiny-mole [99]2 years ago
4 0

For this case we have that by definition, the Greatest Common Factor (GCF) is the largest factor that 2 numbers have in common.

So, we have the following expressions:

42a ^ 5b ^ 3\\35a ^ 3b ^ 4\\42ab ^ 4

We look for the positive integers that divide to 35 and 42 without leaving residue:

42: 1,2,3,6,7,14,21

35: 1,5,7

Thus, the GCF of 42 and 35 is 7

Then, the GCF of the three expressions is:

7ab ^ 3

Answer:

7ab ^ 3

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Alenkasestr [34]
9 hours is the correct answer
9 x 5 = 45
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6 0
3 years ago
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The figure below is an isosceles triangle. What is the perimeter of the triangle in terms of a
professor190 [17]

Hey there! I'm happy to help!

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WHAT IS THE PERIMETER?

The perimeter is just the distance around a shape. If you put a fence around a field, the length of all of the fencing is the perimeter.

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WHAT IS AN ISOSCELES TRIANGLE?

An isosceles triangle is a triangle that has at least two sides that have the same length! In our triangle, we have two sides that have the value of a, so that makes it isosceles!

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THE SOLUTION

In our problem, we want to find the perimeter of this triangle in terms of a and c. When we say in terms of, it just means that our answer will include a and c instead of finding a number value.

The perimeter is the sum of each of these sides. This means that the perimeter is a+a+c, which is also 2a+c.

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I hope that this helps! Have a wonderful day! :D

3 0
3 years ago
Which statement is true regarding the value of the digit in the tenths place of the decimal 19.9993?
levacccp [35]
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6 0
3 years ago
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SVETLANKA909090 [29]
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3 0
3 years ago
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Four different mathematics books, six different physics books, and two different chemistry books are to be arranged on a shelf.
sveta [45]

Answer:

a) 207,360 ways

b)8,709,120  ways

Step-by-step explanation:

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Number of mathematics books = 4

Number of physics books = 6

Number of chemistry books = 2

Part a:

Number of possible arrangement s= 3! 4! 6! 2!= 6*24*720*2= 207360 ways

In this we have included 3! because the books have to be placed in such a manner that the books in each particular subject must all stand together.

Part b:

Similarly the mathematics books must stand together so they are treated as

The total number of books will be

Physics books + Chemistry books+ Mathematics books= 6+2+1(treated as single) = 9

But there are 4 different mathematics books so these can be arranged in 4 ways.

Total number of ways in which these books can be arranged = 9! 4!= 8709120  ways.

4 0
2 years ago
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